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2 years ago

Compare and contrast the solar eclipse seen in this video to a lunar eclipse.

1 answer:

Crank2 years ago

8 0

Answer: sadly, I can’t see the video. However, a lunar eclipse happens when the moon is hidden by the earth’s shadow. A solar eclipse occurs when the moon casts a shadow on the earth.

Explanation: I’m not completely sure if this is what you were looking for, but I hope it helps anyway.

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Which describes a scientist being creative?

AleksandrR [38]

Answer: Sara tries turning a test tube upside down to collect a gas.

A scientist is considered to be creative when he approaches a problem with new different ways. The conventional way is to design an experiment and take detailed notes, reading referenced studies previously done. Sara tries turning a test tube upside down to collect a gas is a creative way as Sara tries something different.

4 0

3 years ago

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6. And what's up with ChiN?

n200080 [17]

I don’t know what’s up with chin man ??

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2 years ago

Which is an si metric unit of measurement that is used to record the heat transfer of a solution in a classroom investigation?

kumpel [21]

The SI unit for heat energy is joule

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3 years ago

A fisherman moves from one end of a boat to another

Naily [24]

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

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2 years ago

A rocket sled accelerates from rest for a distance of 645 m at 16.0 m/s2. A parachute is then used to slow it down to a stop. If

inessss [21]

Answer:

the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake

Explanation:

This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period

v² = v₀² + 2 a₁ x

indicate that the initial velocity is zero

v² = 2 a₁ x

let's calculate

v = $\sqrt {2 \ 15.0 \ 645}$

v = 143.666 m / s

now for the second interval let's find the distance it takes to stop

v₂² = v² - 2 a₂ x₂

in this part the final velocity is zero (v₂ = 0)

0 = v² - 2 a₂ x₂

x₂ = v² / 2a₂

let's calculate

x₂ = $\frac{ 143.666^2 }{2 \ 18.2}$

x₂ = 573 m

as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake

3 0

2 years ago