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solniwko [45]
3 years ago
10

How does matter and energy cycle through an ecosystem?

Chemistry
1 answer:
Ainat [17]3 years ago
6 0
A Cellular respiration alone
Your welcome
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Which product has a bitter taste, is slippery when mixed with water, and can damage skin and eyes?
beks73 [17]

Answer:

sodium hydroxide

Explanation:

its a base and it can damage skin

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What is the overall reaction order for this rate law: rate= k[a][b]?
SpyIntel [72]
The overall reaction order is 2, because you add the orders of the individual components, which each are 1. 
7 0
3 years ago
Suppose that magnesium would react exactly the same as copper in this experiment. how many grams of magnesium would have been us
Vikentia [17]

The solution for this problem would be:

We are looking for the grams of magnesium that would have been used in the reaction if one gram of silver were created. The computation would be:

1 g Ag (1 mol Mg) (24.31 g/mol) / (2mol Ag)(107.87g/mol) = 0.1127 grams of Magnesium

6 0
3 years ago
Which functional group does the molecule below contain
DedPeter [7]

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

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3 years ago
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95. Using the standard enthalpy of formation data in Appendix G, calculate the bond energy of the carbon-sulfur double bond in C
prohojiy [21]

Answer:

+523 kJ.

Explanation:

The following data will be used to calculate the average C-S bond energy in CS2(l).

S(s) ---> S(g)

ΔH = 223 kJ/mol

C(s) ---> C(g)

ΔH = 715 kJ/mol

Enthalpy of formation of CS2(l)

ΔH = 88 kJ/mol

CS2(l) ---> CS2(g)

ΔH = 27 kJ/mol

CS2(g) --> C(g) + 2S(g)

So we must construct it stepwise.

1: C(s) ---> C(g) ΔH = 715 kJ

2: 2S(s) ---> 2S(g) ΔH = 446 kJ

adding 1 + 2 = 3

ΔH = 715 + 446

= 1161 kJ

3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ

4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ

adding (reversed 3) from 4 = 5

ΔH = -1161 + 88

= -1073 kJ

5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ

6: CS2(l) ---> CS2(g) ΔH = 27 kJ

adding 5 + 6 = 7

ΔH = -1073 + 27

= -1046 kJ

7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ

Reverse and divide by 2 for C-S bond enthalpy

= -(-1046)/2

= +523 kJ.

8 0
3 years ago
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