Frank does 2400J of work in climbing a set of stairs. If he does the work in 6
1 answer:
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Answer:a
Explanation:
Given
two bodies are falling with negligible air Resistance and one of the body is given a slight horizontal acceleration
since there is no change in vertical acceleration therefore time taken by both bodies is same irrespective of change in horizontal direction
suppose both start from rest from a height of h
time taken
The only difference is that body with horizontal acceleration will be some distance away from first
Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a = 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°