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makvit [3.9K]
3 years ago
13

A TV satellite broadcasts at a frequency of 5000 MHz, (1 MHz = 1 million Hertz). What is the wavelength of this radiation?

Physics
2 answers:
Nitella [24]3 years ago
5 0

Answer:

\lambda=0.06\ m

Explanation:

Given:

  • frequency of the broadcast, f=5000\ MHz=5\times 10^9\ Hz
  • we have the speed of the radiation equal to the speed of light, c=3\times 10^8\ m.s^{-1}

The broadcast waves are the electromagnetic waves but it can travel only upto a hundred kilometers without any loss of information carried by it.

<u>The relation between the frequency and the wavelength:</u>

\lambda=\frac{c}{f}

\lambda=\frac{3\times 10^8}{5\times 10^9}

\lambda=0.06\ m

goldfiish [28.3K]3 years ago
5 0

Answer:

The wavelength of this radiation is 0.06 m.

Explanation:

Given that,

Frequency = 5000 MHz

We know that,

Speed of light c= 3\times10^{8}\ m/s

We need to calculate the wavelength of this radiation

Using formula of wavelength

\lambda=\dfrac{c}{\nu}

Where, \lambda = wavelength

\nu = frequency

c = speed of light

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{5\times10^{9}}

\lambda=0.06\ m

Hence, The wavelength of this radiation is 0.06 m.

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A 1000-kg car is traveling north at 20.0 m/s. A 1500-kg car is traveling north at 36.0 m/s. The 1500-kg collides with the rear o
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Answer:

B

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The actual mass of a cl 37 atom is 36.966 amu. calculate the mass defect ( amu/atom) for a cl 37 atom​
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Answer:

The mass defect Δm = 0.33626 amu

Explanation:

Given,

The actual mass of a Cl 37 atom, m = 36.966 amu

The atomic number of Cl is 17. Hence, chlorine has <em>17 protons</em>,

Therefore, the Cl 37 has <em>20 neutrons</em>

The mass of 1 proton = 1.00728 amu

The mass of 1 neutron = 1.00867 amu

The mass of 17 protons = 17 x 1.00728 = 17.12886 amu

The mass of 20 protons = 20 x 1.00867 = 20.1734 amu

The total mass of proton and neutron, M = 37.30226 amu

The mass defect is defined as the difference in the sum of the mass of protons and neutrons of the nucleus of an atom to the actual mass of the nucleus.

Therefore,

                        Δm = M - m

                               =  37.30226 - 36.966

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Hence, the mass defect of the Cl 37 atom is, Δm = 0.33626 amu

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