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Ulleksa [173]
3 years ago
13

A car accelerates from rest at a rate of 3 m/s² for 4 seconds. How far did the car travel?

Physics
2 answers:
Gnom [1K]3 years ago
4 0
Distance= distance(initial)+v(initial)*t+0.5at^2
D=0+0*4+0.5*3*4^2
D=24 m
Anna35 [415]3 years ago
4 0

Answer:

24m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 3m/s²

Time  = 4s

Unknown:

Distance covered  = ?

Solution:

To solve this problem, we apply the right motion equation:

             S = ut + \frac{1}{2}at²

S is the distance

u is the initial velocity

t is the time taken

a is the acceleration;

        S  = (0 x 4) +  \frac{1}{2} x 3 x 4²  

        S = 24m

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