Question

A car accelerates from rest at a rate of 3 m/s² for 4 seconds. How far did the car travel?

Answer 1

Distance= distance(initial)+v(initial)*t+0.5at^2
D=0+0*4+0.5*3*4^2
D=24 m

Answer 2

Answer:

24m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 3m/s²

Time  = 4s

Unknown:

Distance covered  = ?

Solution:

To solve this problem, we apply the right motion equation:

             S = ut + $\frac{1}{2}$at²

S is the distance

u is the initial velocity

t is the time taken

a is the acceleration;

        S  = (0 x 4) +  $\frac{1}{2}$ x 3 x 4²  

        S = 24m