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AnnyKZ [126]
3 years ago
12

A 1000-kg car is traveling north at 20.0 m/s. A 1500-kg car is traveling north at 36.0 m/s. The 1500-kg collides with the rear o

f the 1000- kg car and they lock together. Ignoring external forces acting during the collision, what is the velocity of the cars immediately after the collision? (a) 56.0 m/s north (b) 29.6 m/s north (c) 13.6 m/s south (d) 8.00 m/s south (e) 28.0 m/s north
Physics
1 answer:
Papessa [141]3 years ago
7 0

Answer:

B

Explanation:

Use conservation of momentum: Total momentum of the system before is the same as the total momentum after the collision. Since both are moving north, the momentum of both cars is in the same direction, and the total momentum before collision is 1000kg*20m/s + 1500kg*36m/s = 74000kg-m/s.

This is the same amount of momentum after collision, and since they are locked together, their mass is added. The velocity can be found by: 74000kg-m/s ÷ 2500kg = 29.6m/s.

momentum = mass*velocity

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Answer:

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Explanation:

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7 0
3 years ago
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7 0
3 years ago
Convert Rev/min to rad/s x 2pie/60?<br><br> Anyone knows this please?
defon

Answer:

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Explanation:

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\frac{1 rev}{min } = \frac{1 rev}{60 sec}\\\\1 rev = 2\pi rad\\\\So\\\\\frac{1 rev}{min} = \frac{2\pi}{60} rad/s

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Anna007 [38]

True

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Read 2 more answers
The ratio of the potential difference across a conductor to the current in the conductor is called
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Answer:

The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.

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