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VashaNatasha [74]
3 years ago
14

PLEASE HELP!!!

Chemistry
2 answers:
yuradex [85]3 years ago
7 0

This might be right. Im not quite sure. This is what my 5th grade science teacher told me. 'Look at the 2 LR's and add them together. Then look at the total amount which is 32. When you add the 2 LR's you get 17. So subtract 17 from 32 and you get 15. So: C:15 is your answer." (LR's stands for liquid reactants)

10+17=17

Total amount is 32

32-17=15

15 is you mass

Hope this Helps

oee [108]3 years ago
3 0

Its 5g i took the quick check

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Bill, a lab technician, was asked to measure out sodium hydroxide (NaOH) for an experiment in a research lab. He was given a cho
Aleks04 [339]

Answer:

He is wrong . Most accurate is Buret .

Explanation:

The number of significant figure denotes the level of accuracy of a measurement .

Beaker can measure liquid in mL upto significant figure of 2 . That means it can measure volume in terms of 10 , 20 , 30mL etc . It can not measure 25 mL

accurately . The last figure of 28 mL is read by guess in the question . So it is not an accurate measurement .

Similarly , graduated cylinder can measure liquid upto significant figure of 3 .  That means it can measure volume in terms of 11 , 22 , 33 mL etc . It can not measure 25.5  mL accurately . The last figure of 28.3  mL is read by guess in the question . So it is less  accurate measurement .

Similarly , buret  can measure liquid upto significant figure of 4 .  That means it can measure volume in terms of 11.2 , 22.3 , 33.5 mL etc . It can not measure 25.53  mL accurately . The last figure of 28.32  mL is read by guess in the question . So it is most accurate among all the three instrument because it can measure accurately mL upto one tenth of it .

7 0
3 years ago
An element has three stable isotopes with masses of 27.977 amu, 28.976 amu, and 29.973 amu. the heavier two isotopes have an abu
Lera25 [3.4K]
Check attached file for solution.

4 0
3 years ago
Given the following UNBALANCED reaction: NH3 (g) <--> N2 (g) + H2 (g) If 1
Yakvenalex [24]

Answer:

C. 1.35

Explanation:

                                                     2NH3 (g) <-->          N2 (g) +             3H2 (g)

Initial concentration                2.2 mol/0.95L       1.1 mol/0.95L           0

change in concentration        2x                             x                           3x

                                                 -0.84 M                  +0.42M                +1.26M

Equilibrium                       1.4 mol/0.95L=1.47M        1.58 M                   1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0
2 years ago
Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing
Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of AgNO_3 = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of AgNO_3 = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and AgNO_3.

\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles

\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag

From the balanced reaction we conclude that

As, 2 mole of AgNO_3 react with 1 mole of Zn

So, 0.1479 moles of AgNO_3 react with \frac{0.1479}{2}=0.07395 moles of Zn

From this we conclude that, Zn is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag

From the reaction, we conclude that

As, 2 mole of AgNO_3 react to give 2 mole of Ag

So, 0.1479 moles of AgNO_3 react to give 0.1479 moles of Ag

Now we have to calculate the mass of Ag

\text{ Mass of }Ag=\text{ Moles of }Ag\times \text{ Molar mass of }Ag

\text{ Mass of }Ag=(0.1479moles)\times (107.87g/mole)=15.95g

Theoretical yield of Ag = 15.95 g

Experimental yield of Ag = 13.32 g

Now we have to calculate the percent yield.

\% \text{ yield}=\frac{\text{ Experimental yield of }Ag}{\text{ Theretical yield of }Ag}\times 100

\% \text{ yield}=\frac{13.32g}{15.95g}\times 100=83.51\%

Therefore, the percent yield is, 83.51 %

7 0
3 years ago
PLEASE HELP!!!!
Lyrx [107]
Possible answer could be: P/T = k
3 0
3 years ago
Read 2 more answers
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