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KonstantinChe [14]
3 years ago
15

A fact of nature that has been confirmed many times by observation is known as a(n).

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

law(scientific law)

Explanation:

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What is the molarity of the resulting solution when 23.640 g of Mn(ClO4)2 · 6 H2O are added to 200.0 mL of water? WebAssign will
drek231 [11]

Answer:

0.3267 M

Explanation:

To solve this problem, first we calculate how many moles of Mn(ClO₄)₂ are contained in 23.640 g of Mn(ClO₄)₂·6H₂O.

Keep in mind that the crystals of Mn(ClO₄)₂ are hydrated, and <em>we need to consider those six water molecules when calculating the molar mass of the crystals</em>.

Molar mass of Mn(ClO₄)₂·6H₂O = 54.94 + (35.45+16*4)*2 + 6*18 = 361.84 g/mol

Now we <u>proceed to calculate</u>:

  • 23.640 g Mn(ClO₄)₂·6H₂O ÷ 361.84 g/mol = 0.0653 mol Mn(ClO₄)₂·6H₂O = mol Mn(ClO₄)₂

Now we divide the moles by the volume, to <u>calculate molarity</u>:

  • 200 mL⇒ 200/1000 = 0.200 L
  • 0.0653 mol Mn(ClO₄)₂ / 0.200 L = 0.3267 M
6 0
3 years ago
Energy can be changed from potential to kinetic.<br> A.True<br> B.False
vampirchik [111]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Therefore, true. (Also would u mind giving brainliest, you don't have to hehe)

6 0
2 years ago
Describe the difference between Al3+<br> and N3-
wariber [46]
Al3+ is cation due to its positve charge
N3- is an anion due to its negative charge
4 0
3 years ago
A 20.0 g sample of copper at 25.0 °c absorbs 475 j. What is the final temperature of the copper? (specific heat capacity of copp
maks197457 [2]

Given data:

Mass of copper (m)  = 20.0 g

Initial temperature of Copper (T1)=  25 C

Final temperature = T2

Heat absorbed by copper (Q) = 475 J

Specific heat of Copper (c) = 0.385 J/g C

Formula:

Q = mcΔT

   = mc(T2-T1)

475 = 20*0.385*(T2-25)

62.08 = T2-25

T2 = 87.08 = 87.1 C


8 0
3 years ago
A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha
victus00 [196]

Answer:

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2} (at constant pressure)

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K

Putting values in above equation, we get:

\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}

V_2=1.82\times 10^6 L

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

4 0
3 years ago
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