A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force,
in what direction does the rock move?
northeast
east
north
southwest
northeast
east
north
southwest
1 answer:
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Answer:
initial magnitude will be 9 N and direction will be to the right
Explanation:
force= 9N
mass m= 330 grams
acceleartion = a
from newtons 2nd law of motion we write
dP is the chage in momentum dt is time taken and F is the Force applied
this shows that the rate of change of momentum is 9 N
we also know that F= ma
putting values we get
a= 27.27 m/sec^2
The direction of acceleration will along the direction of force applied. So will be the direction of change momentum as in F=ma, mass is the scalar quantity and direction of force dictates the direction of motion. Hence, initial magnitude will be 9N and direction will be to the right
We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,
The difference of the initial and final energy will be equivalent to the work done in the system, therefore
Here,
m = Mass
= Final velocity
G = Gravitational Universal Constant
M = Mass of the Sun
m = Mass of the comet
= Initial Velocity
Rearranging to find the final velocity,
Replacing with our values we have finally,
Therefore the speed is 75653m/s