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ziro4ka [17]
3 years ago
12

A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force,

in what direction does the rock move?
northeast

east

north

southwest

Physics
1 answer:
Cloud [144]3 years ago
7 0

Answer:

Northeast

Explanation:

Let magnitude of the force acting along north and east be F.

One worker pushes it toward north and another pushes it along east with same magnitude.

According to law of parallelogram the Resultant force has direction along northeast as shown in the figure.


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How many protons would the element with the atomic number 10 contain?
galben [10]
The atomic number is the same as the proton number so the answer would be D) 10
3 0
3 years ago
What quantity is the rate of change of velocity? Displacement Acceleration Final velocity
MariettaO [177]

Answer:

Acceleration

Explanation:

The quantity of the rate of change of velocity is termed the acceleration of the body.

Acceleration is the rate of change of velocity with time;

  A  = \frac{v - u}{t}  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

 

7 0
3 years ago
An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

Open tube:

f=\frac{v_s}{2L}         (1)

vs: speed of sound = 343m/s

L: length of the open tube = 0.47328m

You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

Closed tube:

f'=\frac{v_s}{4L'}

L': length of the closed tube = 0.702821m

f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

Next, you use the following formula for the beat frequency:

f_b=|f-f'|=|362.36Hz-122.00Hz|=240.35Hz

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
where F is the force applied, and \Delta x is the stretch of the spring with respect to its equilibrium position. Using the data, we find
k= \frac{15 N}{3.0 cm}=5.0 N/cm

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
\Delta x =  \frac{F}{k}= \frac{30 N}{5.0 N/cm}=6 cm
4 0
3 years ago
Read 2 more answers
Which planet has a tilted axis of rotation similar to that of earth, which means it has seasons?.
MrRa [10]

Answer:

Uranus

Explanation:

it's uranus....

3 0
2 years ago
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