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2 years ago

Please Help Me!

1 answer:

5 0

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

<h3>What is image distance?</h3>

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

1/f = 1/u+1/v........... Equation 1

Where:

f = Focal length of the mirror
v = Image distance
u = object distance

From the question,

Given:

f = 0.45 m
u = 0.25 m

Substitute these values into equation 1 and solve for the image distance

1/0.45 = 1/0.25 + 1/v
2.22 = 4+1/v
1/v = 2.22-4
1/v = -1.78
v = 1/(-1.78)
v = -0.56 m

Hence, The image distance is -0.56 m.

Learn more about image distance here: brainly.com/question/17273444

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3 years ago

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Answer:

option d) is correct

Explanation:

Given:

C = (5/9)(F-32)

For statement I

C = (5/9)F - (5/9)32

let the initial temperature in Fahrenheit be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32

for 1° increase in Fahrenheit

we get

C = (5/9)(1) - (5/9)32 = 1 - (5/9)32

thus,

on comparing the results, statement I is true

now for statement II

let the initial temperature in Celsius be 0

thus,

0 = (5/9)(F) - (5/9)32

F = (9/5)(5/9)32 = 32

for 1° increase in Celsius

we get

1 = (5/9)(F) - (5/9)32

(5/9)F = 1 + (5/9)32

F = (9/5) + 32

F = 1.8 + 32

thus,

on comparing the results, statement II is true

Now, for statement III

let the initial let the initial temperature in Fahrenheit be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32 = - 17.77

for (5/9)° increase in Fahrenheit

we get

C = (5/9)(5/9) - (5/9)32 = (0.3086) - 17.77 = -17.469

thus,

on comparing the results, statement III is false

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