Answer:
Coefficient of kinetic friction = 0.146
Explanation:
Given:
Mass of sled (m) = 18 kg
Horizontal force (F) = 30 N
FInal speed (v) = 2 m/s
Distance (s) = 8.5 m
Find:
Coefficient of kinetic friction.
Computation:
Initial speed (u) = 0 m/s
v² - u² = 2as
2(8.5)a = 2² - 0²
a = 0.2352 m/s²
Nweton's law of :
F (net) = ma
30N - μf = 18 (0.2352)
30 - 4.2336 = μ(mg)
25.7664 = μ(18)(9.8)
μ = 0.146
Coefficient of kinetic friction = 0.146
Answer:
The correct option is;
2.26 × 10⁸
Explanation:
The index of refraction, in a medium, n = The speed of light in air/(The speed of light in the medium)
The speed of light = 299792458 m/s
Given that the index of refraction of water = 1.33, we have;
1.33 = 299792458/(The speed of light in water)
The speed of light in water = 299792458/1.33 = 225407863.58 m/s ≈ 2.26 × 10⁸ m/s
The speed of light in water ≈ 2.26 × 10⁸ m/s
Therefore;
v ≈ 2.26 × 10⁸ m/s.