3 years ago

A car is moving with a constant acceleration. At t = 5.0 s its velocity is 8.0 m/s and at t = 8.0 s its

Physics

1 answer:

spayn [35]3 years ago

4 0

Distance=average velocity x time =((12+8)/2) x 3 =30m

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If a car goes along a straight road heading east and speeds up from 45 ft/s to 60. ft/s in 5 sec, calculate the

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Question 1 of 10

Dahasolnce [82]

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They have the same rate of motion.

Explanation:

Electromagnetic radiation is a type of energy that is commonly known as light. Generally, light travels in waves, and all electromagnetic radiation travels at the same speed, which is about 3.0 × 108 ms− 1 through a vacuum.

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2 years ago

A particle of mass 2.37 kg is subject to a force that is always pointed towards East or West but whose magnitude changes sinusoi

Pavlova-9 [17]

Answer:

$v(1.5)=0.7648\ m/s$

Explanation:

<u>Dynamics</u>

When a particle of mass m is subject to a net force F, it moves at an acceleration given by

$\displaystyle a=\frac{F}{m}$

The particle has a mass of m=2.37 Kg and the force is horizontal with a variable magnitude given by

$F=2cos1.1t$

The variable acceleration is calculated by:

$\displaystyle a=\frac{F}{m}=\frac{2cos1.1t}{2.37}$

$a=0.8439cos1.1t$

The instant velocity is the integral of the acceleration:

$\displaystyle v(t)=\int_{t_o}^{t_1}a.dt$

$\displaystyle v(t)=\int_{0}^{1.5}0.8439cos1.1t.dt$

Integrating

$\displaystyle v(1.5)=0.7672sin1.1t \left |_0^{1.5}$

$\displaystyle v(1.5)=0.7672(sin1.1\cdot 1.5-sin1.1\cdot 0)$

$\boxed{v(1.5)=0.7648\ m/s}$

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3 years ago