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igomit [66]
2 years ago
9

PLEASE HELP ASAP Label the correct descriptors (volume, temperature, pressure, moles) *

Chemistry
1 answer:
Zanzabum2 years ago
5 0

Explanation:

1. volume

2. pressure

3. moles

4. temperature

5. temperature

6. moles

7. pressure

8. volume

9. pressure

10. volume

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2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
damaskus [11]

Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{1 \times 196}{26}  =  \frac{196}{26}   \\ = 7.538461...

We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

3 0
2 years ago
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. part a if the initial concentration of no
luda_lava [24]

Answer:

[NO] = 1.72 x 10⁻³ M.  

Explanation:

  • For the reaction:

<em>2NO(g) ⇌ N₂(g)+O₂(g),</em>

Kc =  [N₂][O₂] / [NO]².

  • At initial time: [NO] = 0.171 M,  [N₂] = [O₂] = 0.0 M.
  • At equilibrium: [NO] = 0.171 M - 2x ,  [N₂] = [O₂] = x M.

∵ Kc =  [N₂][O₂] / [NO]².

∴ 2400 = x² / (0.171 - 2x)² .

<u><em>Taking the aquare root for both sides:</em></u>

√(2400) = x / (0.171 - 2x)  

48.99 = x / (0.171 - 2x)  

48.99 (0.171 - 2x) = x  

8.377 - 97.98 x = x

8.377 = 98.98 x.

∴ x = 8.464 x 10⁻².

<em>∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M.  </em>

<em>∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.</em>

3 0
3 years ago
As fast as possible really fast really fast
vichka [17]

#1

\\ \rm\longmapsto Density=\dfrac{Mass}{Volume}

#2

  • Volume=120mL
  • Density=0.75g/ml

\\ \rm\longmapsto Mass=Density\times Volume

\\ \rm\longmapsto Mass=120(0.75)

\\ \rm\longmapsto Mass=90g

7 0
3 years ago
Class 8 chemistry : metals and non metals describe the process of formation of coal in the nature
Ilia_Sergeevich [38]

ksishissbususus7wbwusbsisbssisbs8s

Explanation:

mark me as a brainlist

5 0
3 years ago
Read 2 more answers
I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

2.  Use the equation P₁V₁ = P₂V₂.  Solve for V₂.  

(3.05 L)(870 kPa) = (969 kPa)(V₂)  

V₂ = 2.74 L.  

3.  Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.  

(3.32 L)/(360 K) = (4.50 L)/(T₂)  

T₂ = 488 K.

4.  Do the same as above, but for V₂.  

(5.10 L)/(-56°C) = V₂/(-82°C)  

V₂ = 7.47 L

5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)  

V₂ = 38.6 L

6.  Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)  

n₂ = 2.85 mol

7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)  

T₂ = 319 K

8.  Do the same as above, but for P₂.  

In this specific case, however you will need to convert units.  Since both temperatures don't have the same sign, the ratio won't come out right.  Convert to Kelvin.  Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K  25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0
3 years ago
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