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lyudmila [28]
3 years ago
7

Hello

Chemistry
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

Phloem

Explanation:

Xylem transports water by action of trandpiriation pull, capillary action and root pressure. Phloem consists of sieve tubes and companion cells. The phloem is made of tubes and cells basically.

denis-greek [22]3 years ago
3 0

Answer:

B

Explanation:

because Phloem tissue consists of a group of specialized cells. Sieve tubes are elongated tubular conducting channels of phloem through which food is transported. The contents of phloem can move in the upward as well as in the downward direction. Therefore, they form two-way traffic in plants.

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If you dissolve 8.50 g of ca(no3)2 in 755 ml of distilled water what is the concentration in molarity of the calcium nitrate sol
Zanzabum
Molarity is defined as the number of moles of solute in 1 L of solution 
the mass of Ca(NO₃)₂ present - 8.50 g
therefore number of moles of Ca(NO₃)₂ - 8.50 g / 164 g/mol = 0.0518 mol
the volume of solution prepared is 755 mL 
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4 0
3 years ago
How is the mass of 1 mole of an element determined? O A. It is equal to the atomic mass times Avogadro's number. O B. It is the
evablogger [386]

Answer:

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Give the numbers of significant figures indicated 60.1<br><br> 0 <br> 3 <br> 1 <br> 2
denpristay [2]
3 significant figures
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The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

3 0
3 years ago
Why would an atom become an ion?
crimeas [40]

Answer:

c

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