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shutvik [7]
3 years ago
10

(a) Calculate Earth's average speed relative to the Sun. (b) What is its average velocity over a period of one year?

Physics
1 answer:
JulsSmile [24]3 years ago
8 0

i think more info needed.

radius of orbit, eg

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Two samples of water are mixed together.
Anon25 [30]
<h3><u>Answer;</u></h3>

A.75°C

<h3><u>Explanation</u>;</h3>

Let the change in temp of cold water be  x degrees,

while that of  hot water be 100 - x degrees.

Heat exchange =  mcΔt

Ice

Δt = x

m = 0.50 kg

c = 4.18 kJ/kg*°C

Hot water

Δt = 100 - x

m = 1.5 kg

c = 4.18

But;

Heat lost = heat gained

0.50 * c * x = 1.5 * c * (100 - x)          

0.50 *x = 1.5*(100 - x)                          

0.5x = 150 - 1.5x                                  

0.5x + 1.5x = 150 - 1.5x + 1.5x            

2x = 150                                              

x = <u>75° C</u>

Hence; the equilbrium temperature will be 75° C

7 0
3 years ago
Were there experiences in his life that led to his interest in science and the study of the atom?
charle [14.2K]

Answer:

The right answer is Democritus

Explanation:

He experienced bonding with his father which strongly resulted his interest in science and to the study of the atoms ;)

Your welcome

5 0
2 years ago
Read 2 more answers
Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
Mila [183]

Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

                       = 427.5

Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

        = \frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}

       = 10.13 \times 10^{-4}

Therefore, largest size is as follows.

            Largest size = 2a

                                 = 2 \times 10.13 \times 10^{-4}

                                 = 20.26 \times 10^{-4}

Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
3 years ago
Help needed!
Sliva [168]

Answer:

for question 5 its

Explanation:

Through Brahe's astronomical measurements and Kepler's own drawings of the geometrical relationship between the Sun and Mars in various parts of the planet's orbit, Kepler discovered that planets moved faster when they were closer to the Sun.

4 0
3 years ago
What is the number on the top left
Anettt [7]
The mass number (the amount of protons and neutrons that element has altogether)
3 0
3 years ago
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