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Juliette [100K]
3 years ago
12

A 68.5‐kg astronaut is doing a repair in space on the orbiting space station. She is at rest relative to the space station. She

then throws a 2.25‐kg tool away from the space station at 3.20 m/s. With what speed and in what direction will she being to move?
Physics
1 answer:
xeze [42]3 years ago
7 0

Answer:

The velocity of astronaut will be 0.105 m/s in opposite direction of the tool.

Explanation:

Given that,

Mass of the Astronaut, m = 68.5 kg

Mass of the the tool, m' = 2.25 kg

Speed of tool, v' = -3.2 m/s (direction is sway from space station)

It is required to find the speed of the astronaut. The momentum will remain conserved. So,

mv=m'v'

v is the speed if Astronaut

v=\dfrac{m'v'}{m}\\\\v=\dfrac{2.25\times (-3.2)}{68.5}\\\\v=-0.105\ m/s

So, the velocity of astronaut will be 0.105 m/s in opposite direction of the tool.

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Find the work w1 done on the block by the force of magnitude f1 = 75.0 n as the block moves from xi = -1.00 cm to xf = 3.00 cm .
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3 years ago
Aliya deposited half as much money in a savings account earning 1.9% simple interest as she invested in a money market account t
yanalaym [24]

Let <em>A</em> be the amount of money that Aliya deposited in the savings account. Since <em>A</em> is half as much as money as she invested in a money market account, then the amount that she invested in the market account is <em>2A.</em>

<em />

Express the interest that Aliya earned in terms of A. Set it equal to the amount of $297.60 and then solve for <em>A</em>.

Since the savings account gives 1.9% simple interest, the total amount of interest that she will earn from the savings account is 1.9% of A, which is equal to:

\frac{1.9}{100}\times A

Since the money market account gives 3.7% simple interest, the total amount of interest that she will earn from the money market account, is 3.7% of <em>2A</em>, which is equal to:

\frac{3.7}{100}\times2A

Add both interests in terms of A and simplify the expression:

\begin{gathered} \frac{1.9}{100}\times A+\frac{3.7}{100}\times2A \\ =\frac{1.9}{100}\times A+\frac{7.4}{100}\times A \\ =(\frac{1.9}{100}+\frac{7.4}{100})\times A \\ =\frac{1.9+7.4}{100}\times A \\ =\frac{9.3}{100}\times A \end{gathered}

The expression (9.3/100)*A represents the total interest after one year. Then:

\begin{gathered} \frac{9.3}{100}\times A=297.60 \\ \Rightarrow A=\frac{100}{9.3}\times297.60 \\ \Rightarrow A=\frac{100\times297.60}{9.3} \\ \Rightarrow A=\frac{29760}{9.3} \\ \Rightarrow A=3200 \end{gathered}

Use the value of <em>A</em> to find the amount that was invested in the money market account:

2A=2\times3200=6400

Therefore, Aliya deposited 3200 in a savings account and 6400 in a money market account.

3 0
1 year ago
An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux
zhenek [66]

Answer:

\phi=1.56\times 10^{-5}\ Wb

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H

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L=\dfrac{N\phi}{I}, \phi is magnetic flux

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So, the magnetic flux is 1.56\times 10^{-5}\ Wb.

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