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2 years ago

Some individuals have developed to use echolocation and thus able to see even if they are blind, True or False

Physics

1 answer:

aliya0001 [1]2 years ago

7 0

Answer:

please give me brainlist and follow

Explanation:

The good news is that anyone can learn this ability, blind or sighted. Lore says that echolocation requires probably as much commitment as developing expert long cane skills. Lore acknowledges that, while there are many people who have some basic echolocating skills, there are only a few who really master this ability.

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A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r

sergij07 [2.7K]

Answer:

The workdone is $W = 1.712 *10^{-20 } \ J$

Explanation:

From the question we are told that

The potential difference is $V = 107 mV = 107 *10^{-3} \ V$

Generally the charge on $Na^{+}$ is $Q_{Na^{+}} = 1.60 *10^{-19 } \ C$

Generally the workdone is mathematically represented as

$W = Q_{Na^{+}}V$

=> $W = 1.60 *10^{-19 } * 107 *10^{-3}$

=> $W = 1.712 *10^{-20 } \ J$

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2 years ago

Just the answer (PLSS)

Salsk061 [2.6K]

The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.

<h3>When was Einstein miracle year?</h3>

The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.

His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.

Learn more about Albert Einstein:brainly.com/question/2964376

#SPJ1

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1 year ago

how much chemical energy must be supplied to a car engine if we want it to produce 5000J of kinetic energy and it is 45% efficie

vagabundo [1.1K]

Here i state the conservation of energy rule and use that to justify my answer. I showed how to manipulate percentages to get the final answer of 11000J (2sf). Hope I'm right xx

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2 years ago

A particle has a charge of -4.25 nC.

SpyIntel [72]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

Electric field is given by

$E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C$

The magnitude is 611.32 N/C

The electric field will point straight down as the sign is negative towards the particle.

$E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m$

The distance from the electric field is 1.71436 m

4 0

2 years ago

Read 2 more answers

Why does the area around the equator stay about the same temperature year round?

Verdich [7]

Axial Tilt and Sun Energy

This axial tilt means that during the Earth's journey around the sun the poles receive varying amounts of sunlight. The equator, however, receives relatively consistent sunlight all year. The consistency of energy means the equator's temperature stays relatively constant all year.

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2 years ago