Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = 
= sin θ
sin θ = y / L
we substitute
= m λ
with the initial data we look for the distance between the lines
d = 
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Answer:1.55 times
Explanation:
Given
First wavelength
Second wavelength
According wien's diplacement law
where 
T=Temperature
Let 
be the temperatures corresponding to 
respectively.
Thus object with 
is 1.55 times hotter than object with wavelength 
Answer:
m = 3.91 kg
Explanation:
Given that,
Mass of the object, m = 3.74 kg
Stretching in the spring, x = 0.0161 m
The frequency of vibration, f = 3.84 Hz
When the object is suspended, the gravitational force is balanced by the spring force as :
k = 2276.52 N/m
The frequency of vibration is given by :
m = 3.91 kg
So, the mass of the object is 3.91 kg. Hence, this is the required solution.
the answer should be:
When the buoyant force is equal to the force of gravity
