Can someone please answer this question I'm doing the test now?
Answer:
Peak current = 16.9 A
Explanation:
Given that
RMS voltage = 120 Volts
AC is connected across resistance
now by ohm's law
now peak value of current will be given as
The car undergoes an acceleration <em>a</em> such that
(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)
90 m = 0.09 km, so
(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)
Solve for <em>a</em> :
<em>a</em> = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²
Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that
<em>F</em> = (4500 kg) (11,250 km/h²)
Recall that Newtons (N) are measured as
1 N = 1 kg • m/s²
so we should convert everything accordingly:
11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²
Then the force is
<em>F</em> = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N
Answer:
Explanation:
Using Snell's law
n₁ sinθ₁ = n₂ sinθ₂
for 420 nm wavelength
where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660
1.00 × sin 30° = 1.660 sinθ₂
sinθ₂ = 0.3012
θ₂ = sin⁻¹ 0.3012 = 17.53°
for 690 nm wavelength
n₁ sinθ₁ = n₂ sinθ₂
sinθ₂ = 0.5 / 1.630
θ₂ = sin⁻¹ 0.3067 = 17.86°
the angle between the two beam = 17.863° - 17.53° = 0.333°
Answer:
B. Kinetic energy.............
