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In-s [12.5K]
4 years ago
15

Beta particles will:

Physics
2 answers:
Mademuasel [1]4 years ago
8 0

Answer is C. Hope I helped!

solong [7]4 years ago
3 0

Beta particles are electrons, which carry negative charge.

Charge isn't affected by magnets, unless it's moving.  If it's moving, THEN it's electric current, and current feels a force toward or away from magnets.  

This question doesn't say whether the beta particles are moving, so we have to assume that they're just laying there, and they don't even know that there's a magnet nearby.

So beta particles will not be affected by either pole of a magnet. <em>(C)</em>

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Answer:

i think maybe because it has more than 6 or 5 parts.

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4 years ago
A mile is equivalent to 1.6 km. When you are driving at 60 miles per hour, what is your speed in meters per second?
yKpoI14uk [10]
FIrst, just write down what we know :)

1. 1 mile = 1.6klm
2. There are 3600 seconds in an hr (<em>60s x 60mins = 3600</em>).

Now to get to <em>meters per second</em> (m/s) we need to first work out <em>meters per </em><em>hr</em> (simply convert miles to klm and then multiply by 1000)<em>.</em>

60 x 1.6 = 96 klm/hr x 1000 = 96,000 meters/hr

Now we know this, we can simply divide the meters per hr by <em>how many seconds there are in 1hr</em> to get meters per second:

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3 years ago
A nuclear particle with no charge
pishuonlain [190]
A nuclear particle with no charge is a neutron
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3 years ago
Summary of set.........
Brrunno [24]

Answer:

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7 0
3 years ago
Read 2 more answers
What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 du
Crank

<u>Answer:</u>

Work done done by a system on its environment is W=40 Joules

<u>Explanation:</u>

<u>Given:</u>

Ideal gas is maintained at a constant pressure P=200 \frac{N}{m^{2}}

Change in Volume d v= -0.2 m^{3}

<u>To find:</u>  

Work done by a system during an Isobaric Process

<u>Solution:</u>  

In a Isobaric Process, constant pressure is maintained, P=200 \frac{N}{m^{2}}

According to the formula,

work done  \bold{W=P \times d v}

Substitute the values of pressure and change in volume in the above formula,

=200 \times -0.2

=40 \text { Joules }

<u>Result:</u>  

Work done done by a system W= -40 Joules

8 0
3 years ago
Read 2 more answers
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