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slavikrds [6]
3 years ago
11

The half-life of carbon-14 is 5730 years. how long will it take for 7/8 of a sample of carbon-14 to decay

Physics
2 answers:
wlad13 [49]3 years ago
5 0
The half life of Carbon-14 is 5730 years, how many years would it take for 7/8 of the original amount to decay? 

<span>Can somebody please help with this problem. I *think* I understand the basics of what a half life is. If I learned correctly, its the amount it takes for half of a sample to decay. It should also happen exponentially, 1/2 remaining after one half life, 1/4 after the second, 1/16 after the third etc. I'm still a little shaky though. Could somebody please clarify what exactly a half life is and how it can be determined (i.e. how to find the time it would take for 7/8 to decay) </span>


andrezito [222]3 years ago
3 0

Answer:

B) 17,190 years

Explanation:

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a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how
NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = 6\times 10^6\ J

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s

The time taken to lift the load is 141.26626 seconds

5 0
3 years ago
The ice cap at the North Pole may be 1000 m thick, with a density of 920 kg/m3. Find the pressure at the bottom and the correspo
bija089 [108]
<span>Pice=920kg/m^3 deltaP=PgH=920kg/m^3 X 9.80665m/s^2 X 1000m = 9022118 Pa P=Po + deltaP=101.325 + 9022 = 9123kPa</span>
7 0
3 years ago
What type of radiation does not have to be observed above earths atmosphere? Visible light, X rays, Gamma rays, Ultraviolet radi
juin [17]
The correct answer is visible light.

Hope this helps.
6 0
3 years ago
Fan can accelerate from the starting blocks to running 11m/s down the track in 5 seconds. What is her acceleration?
Firdavs [7]
To answer this question we subtract the initial velocity from her final velocity. On the starting blocks the initial velocity was 0 m/s. Her final velocity was 11 m/s.t = 11m/s - 0 m/s, so the change in velocity is 11m/s. Time was 5 seconds.Plug it into the formula: 11 m/s ÷ 5 s= 2.2 m/s<span>2</span>
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3 years ago
A bar on a hinge starts from rest and rotates with an angular acceleration α = 15+4t, where α is in rad/s2 and t is in seconds.
Arisa [49]

Answer:

230.53°

Explanation:

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t =2mins = 2 × 60 = 120sec.

α = angle in rad / 2^2

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23 = angle/4

23× 4 = angle in radian

92 = angle in radian

But π rad = 180°

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Therefore

92 rad = 92 ×180/π = 5270.53°

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230.53°

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3 years ago
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