Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
Diamonds and iron, as they can't be easily put back or recreated. Remember to make sure yourself.
Hope this helps :)
Answer:
Explanation:
We shall apply here Doppler's effect in optics . The formula is as follows
Δλ is change in wavelength , λ is original wavelength , v is velocity and c is velocity of light
Δλ = 685 - 590 = 95 nm
λ = 685
95 / 685 = v / 3 x 10⁸
v = .416 x 10⁸ m / s
= 4.16 x 10⁷ m /s
R2^ 2 / R1 ^2 = g1 / g2 = 38
<span>R2 = R1 x √38 = 6.1644* R1 </span>
<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>
A) <u>Weight = mass × acceleration (due to gravity) </u>
= 60×9.8
= 588 N
<u>B) Potential energy = mass x gravity x change in height
</u>
1,000 = 60.0 x 9.8 x h
h = 1.7 m
<u>C) Kinetic energyF = potential energyI
</u>
KEF = 1/2mv2
PEI = mgh = 1,000 J
1/2mv2 = 1,000
1/2(60.0)v2 = 1,000
v2 = 33.33
v = 5.77 m/s
