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Makovka662 [10]
3 years ago
7

Use the relative size of the 3s orbital below to answer the following questions about orbitals A–D. (a) Which orbital has the hi

ghest value of n? (b) Which orbital(s) have a value of l = 1? l = 2? (c) How many other orbitals with the same value of n have the same shape as orbital B? Orbital C? (d) Which orbital has the highest energy? Lowest energy?
Chemistry
1 answer:
notka56 [123]3 years ago
6 0

Answer:

a) Option D

b) A and C, I = 1

B and D, I = 2

c) There are three orbitals that have the same value of n and the form as option B. there are 5 orbitals d for the values ​​of n. Four have the same shape as option B, the fifth has the same shape as the D orbital. On the other hand, there are two orbitals with the same shape as C. Each p orbitals has the same shape. Therefore, there are two orbitals with the same value of n and the same shape as the option C orbital.

d) highest energy: D

lowest energy: C

Explanation:

a) If the value of n increases, the size of the orbital would increase, and since option D is the largest, this means that it has the highest value of n.

b) Quantum number means the number of nodes in each orbital. Since A and C are p-type orbitals, they only have a single node, therefore I = 1. Regarding B and D, they are both d orbital orbitals, and the quantum number for this type of orbital is 2, therefore I = 2

d) The energy level is directly proportional to the value n. As n increases, the energy level increases, therefore, D has the highest energy because it has the largest number of n, and C has the lowest energy because the value of n is small.

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Delicious77 [7]

Answer:

1.51

⋅

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Explanation:

This is a pretty straightforward example of how to sue Avogadro's number to figure out the number of molecules present in a given sample.

In your case, the sample is said to contain  

2.50

moles of water. Now, a mole is simply a very, very large collection of molecules. In order to have  

1

mole of a molecular compound you need your sample to contain  

6.022

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4 years ago
How many atoms make up a molecule of ethanol (C2H6O)? 1 12 8 9 3
pogonyaev

Answer:

There are nine atoms in a molecule of ethanol.

Explanation:

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3 years ago
Predict the shape, state the hybridization of the central atom, and give the ideal bond angle(s) and any expected deviations for
Sati [7]

SeO₄²⁻ is state the hybridization of the central atom, and give the ideal bond angle(s).

<h3>What is potassium hydroxide?</h3>

Potassium hydroxide, also known as lye, is a chemical substance with the formula KOH. It is also known as caustic potash and is available in a variety of forms such as pellets, flakes, and powders. It has a variety of chemical, industrial, and manufacturing applications.

Potassium hydroxide, sometimes known as caustic potash, is an inorganic chemical with the formula KOH. KOH is a classic strong base, along with sodium hydroxide. It has numerous industrial and specialty applications, the majority of which take advantage of its caustic nature and acid reactivity.

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6 0
1 year ago
Determine the quantum numbers n and l of the electron removed when bi is ionized to bi+
lozanna [386]

Electronic configuration of bismuth is given as:

1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}4f^{14}5d^{10}6s^{2}6p^{3}

When electron is removed from bismuth then bismuth is ionized to Bi^{+}, the electronic configuration becomes:

1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}4f^{14}5d^{10}6s^{2}6p^{2}

Now, n represents the principal quantum number which determines the distance from the orbital of the electrons i.e. size of the orbital and its energy.

Thus, outer most electron is present in shell number 6. Thus, principal quantum number is (n=6).

Now, l represents the azimuthual quantum number which determines the shape of an orbital.

Now, if the outer most electron is present in s orbital then the l =0, if the outer most electron is present in p orbital then the l =1, if the outer most electron is present in d orbital then the l =2, if the outer most electron is present in f orbital then the l =4 and if the outer most electron is present in d orbital then the l =2, if the outer most electron is present in h orbital then the l =5.

l 0 1 2 3 4 5

Letter s p d f h

Thus, azimuthual quantum number is 1 as the outer most electron is present in the p orbital.



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3 years ago
Which statement correctly describes whether a compound is a pure substance? 
luda_lava [24]

A compound is a pure substance because its molecule cannot be broken down into simpler particles by physical means.

6 0
4 years ago
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