Answer: The equilibrium constant,
, for the reaction is 0.061.
Explanation:
Initial concentration of
=
Equilibrium concentration of
=
The given balanced equilibrium reaction is,

Initial conc. 0.039 M 0 M 0 M
At eqm. conc. (0.039-x) M (x) M (x) M
Given : (0.039-x) = 0.012
x = 0.027
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get :

The equilibrium constant,
, for the reaction is 0.061.
B. compound
source is Glencoe Science book grade 7.
Also I just happening to be learning about this at school
Answer:
Single displacement reaction.
Explanation:
Hello!!
In this case, since the reaction between silver nitrate and copper metal is:

As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.
Therefore, this is a single displacement reaction, because the the lonely copper displaced the silver.
Best regards!
Dipole-dipole interactions, and London dispersion interactions
The question is incomplete, complete question is :
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.
Answer:
33.11 millimoles of acetate we will need to add to this solution.
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
Where :
tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid
[salt] = Concentration of salt
[Acid] = Concentration of salt
We have:
pH = 5.26

[salt] =
= ?
[acid] = ![[CH_3COOH]=10.0 mmol](https://tex.z-dn.net/?f=%5BCH_3COOH%5D%3D10.0%20mmol)
![[CH_3COO^-]=33.11 mmol](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D33.11%20mmol)
33.11 millimoles of acetate we will need to add to this solution.