Help please need to find the frequency of the wave

Chemistry

1 answer:

Lapatulllka [165]3 years ago

3 0

E=hf h=6.63*10^-34 f=8.66*10^14 E=6.63*10^-34*8.66*10^14=57.4*10^-20 joules

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How many moles are in 3.57 x 10 32 particles Ca?

valentina_108 [34]

Answer:

$\boxed {\boxed {\sf 592,826,303.6 \ moles \ of \ Ca }}$

Explanation:

To convert from moles to particles, we must Avogadro's Number.

$6.022*10^{23}$

This number tells us the number of particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, it is the particles of calcium in 1 mole of calcium.

$6.022*10^{23} \ particles \ Ca / mole \ Ca$

We can use Avogadro's Number as a ratio or fraction.

$\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Multiply this by the given number of particles (3.57*10³²).

$3.57*10^{32} \ particles \ Ca*\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Flip the fraction so the particles of calcium will cancel out.

$3.57*10^{32} \ particles \ Ca*\frac{1 \ mol \ Ca}{6.022 *10^{23} \ particles \ Ca}$

$3.57*10^{32} *\frac{1 \ mol \ Ca}{6.022 *10^{23} }$

$\frac{3.57*10^{32} \ mol \ Ca}{6.022 *10^{23} }$

$592826303.6 \ mol \ Ca$

There are 592,826,303.6 moles of calcium in 3.57*10³² particles of calcium.

8 0

2 years ago

Tetrachloromethane, CCl4, is classified as a

Soloha48 [4]

Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.

Reason:
A chemical compound is a chemical substance composed of element (of same or different type) that are bonded in a fixed proportion. Depending upon the type of element, bond can be ionic or covalent. In present case, tetrachloromethane i.e. CCl4 has one 'C' atom that is covalently bonded to four 'Cl' atoms.

8 0

3 years ago

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Will reward brainliest !!!

Anna [14]

The best answer choice here would be 'Combination'

8 0

3 years ago

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The element chlorine is represented by the symbol ____. (Capitalization is important.) Answer for Blank 1:

gavmur [86]

It should be Cl
next to the capital C is an L btw