Explanation:
The prefix trans- and its variant tra- mean "across".
A translucent substance allows some light to go "across" it to the other side. Also, think about a transparent substance: it allows light to go "across" it; or a translation, it is a going "across" from one language into another.
Part (a): The masses
From the periodic table:
molar mass of copper = 63.5 grams
This means that:
mass of 2..06 moles = 2.06 * 63.5 = 130.81 grams
comparing this mass with the 222 grams of silver, we will find that the mass of silver is greater.
Part (b): The atoms:
number of moles = mass / molar mass
number of moles of silver = 222 / 107.8 = 2.059 moles
each mole contains Avogadro's number of atoms.
Since number of moles of copper is slightly larger than nuber of moles of silver, this means that the number of atoms in the copper sample would be more.
Answer:
X5Y2
Explanation:
% composition of X = 52.2%
% composition of Y = (100 - 52.2) = 47.8%
This means that there are 52.2g of X and 47.8g of Y in the compound
To calculate the empirical formula of the compound, we first convert the gram value to mole value by dividing by their molar masses.
X = 52.2g/42.3g/mol = 1.234mol
Y = 47.8g/96.7g/mol = 0.494mol
Next, we divide each mole value by the smallest value (0.494mol)
X = 1.234mol ÷ 0.494mol = 2.49
Y = 0.494mol ÷ 0.494mol = 1
We multiply each value by 2
X = 2.49 × 2 = 4.98
Y = 1 × 2 = 2
The simple ratio of X:Y is 5:2, hence, their empirical formula is X5Y2.
Answer:
1,42M
Explanation:
Molar concentration is given in moles of solute per liter o solution. Assuming you have 100g of solution:
10g KCl × (1mol / 74,55g) = <em>0,134 moles of KCl</em>
As you have 100g of solution:
100g × (1mL / 1,06g) × (1L / 1000mL) = <em>0,0943L</em>
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That means molar concentration is:
0,134 moles of KCl / 0,0943L = <em>1,42M</em>
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I hope it helps!
Answer:
Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.
Explanation: