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Aleonysh [2.5K]
3 years ago
13

A single six-sided fair die is tossed, what is the probability of obtaining a number greater than 4?

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

1/3 or 0.333333

Step-by-step explanation:

The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4

---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of

the six faces.Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.

So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6

Now that numbers greater than 4 are 5 and 6

So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333

Answer 1/3 or 0.33333

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Helps me solve this problem please
AysviL [449]

Answer:

The slope is -3/7 so B

Step-by-step explanation:

Just turn this into slope-intercept form.

what you do is subtract 3x so that it's moved to the right side.

It should look like this -7y = 12 - 3x

Then just divide all numbers by 7 so everything is simplified

It should look like this y = -3/7x - 12/7

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8 0
3 years ago
Write the name of the period that has the digits 913 in 913256
solniwko [45]
I don't understand what your asking
8 0
3 years ago
Read 2 more answers
Which equations represent functions?
never [62]

Answer:

2x + 3y = 10,  3y = 18  (in both cases, for each input x, there is exactly one output y.

Step-by-step explanation:

3y = 10 - 2x, or y = (1/3)(10 - 2x)   Yes, this is a function.

4x = 16 → x = 4        NOT a Function, because for x = 4 there are an infinite number of possible y -values

2x - 3 = 14 →  2x = 17  →  x = 17/2  Not a function.  See reason given above.

3y = 18 →  y = 6   Function

2x = 14.6   →  x = 7.3  Not a function.  See reason given above

4 0
3 years ago
9x²+12xy+4y²???PLEASE HURRY 15 POINTS~
irakobra [83]

Answer:

(3x+2y)²

Step-by-step explanation:

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6 0
3 years ago
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In Happyville, the ideal family has four children, at least two of which are girls. If you randomly select a Happyville family t
sleet_krkn [62]

Answer:

0.3125 = 31.25% probability that it is not ideal.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or they are not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.5 probability of a children being a girl:

This means that p = 0.5

If you randomly select a Happyville family that has four children, what is the probability that it is not ideal?

Not ideal is less than two girls, so this is P(X < 2).

Four children means that n = 4. So

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.5)^{0}.(0.5)^{4} = 0.0625

P(X = 1) = C_{4,1}.(0.5)^{1}.(0.5)^{3} = 0.25

P(X < 2) = P(X = 0) + P(X = 1) = 0.0625 + 0.25 = 0.3125

0.3125 = 31.25% probability that it is not ideal.

7 0
2 years ago
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