All categories

3 years ago

I NEED HELP PLEASE! THANKS :)

Mathematics

2 answers:

Marianna [84]3 years ago

7 0

Answer:

 $y = 2 \: cos \: (\frac{1}{3} x)$ 

option C is the right option.

Explanation:

General expression of a cosine function is:

y=A cos k X

where A is amplitude and 2 pi/k is its period.

In our case,

 $- y = 2 \: cos \: (\frac{1}{3} x) \:$ 

has :

 $amplitude = 2 \\ period = 2\pi \times 3 = 6\pi$ 

hence, the right answer is of option C

hope this helps...

Good luck on your assignment..

Gala2k [10]3 years ago

6 0

Answer:

The third option should be correct. Goodluck!

You might be interested in

the equation f=v+at represents the final velocity of an object f, with an initial velocity,v, and an acceleration rate a,over ti

vfiekz [6]

F=v+at
f-v=at
(f-v)/t =a
the first choice is correct :)

3 0

3 years ago

Joshua gave away 1/3 of his marbles to Kale.If Kale got 25 marbles,how many marbles did Joshua have at first?

OLEGan [10]

Answer:

Step-by-step explanation:

joshua - x

kale - 1/3x

1/3x = 25

x = 25(3)

x = 75

6 0

2 years ago

Selma uses a jogging trail that runs through a park near her home. The trail is a loop that is 3/4 of a mile long. On Monday, Se

KIM [24]

(3/4) / (1/6) =
3/4 * 6/1 =
18/4 =
4.5 miles per hr <==

7 0

3 years ago

Pls help!! will give all my points

sergejj [24]

when x=-2

-10(-2)+y=4

y=4-20

y=-16

when x=-1

-10(-1)+y=4

y=-6

when x=0

-10(0)+y=4

y=4

when x=1

-10(1)+y=4

y=14

when x=2

-10(2)+y=4

y=24

8 0

3 years ago

Read 2 more answers

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time

kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean x₁ = 25

Sample variance s₁ = 27

Sample size n₁ = 45

Old machine

Sample mean x₂ = 23

Sample variance s₂ = 7,56

Sample size n₂ = 36

Test Hypothesis:

Null hypothesis H₀ x₂ - x₁ = d = 0

Alternative hypothesis Hₐ x₂ - x₁ < 0

CI = 90 % ⇒ α = 10 % α = 0,1 z(c) = - 1,28

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √s₁² / n₁ + s₂² / n₂

s₁ = 27 ⇒ s₁² = 729

n₁ = 45 ⇒ s₁² / n₁ = 16,2

s₂ = 7,56 ⇒ s₂² = 57,15

n₂ = 36 ⇒ s₂² / n₂ = 1,5876

√s₁² / n₁ + s₂² / n₂ = √ 16,2 + 1.5876 = 4,2175

z(s) = (23 - 25 )/4,2175

z(s) = - 0,4742

Comparing z(s) and z(c)

|z(s)| < | z(c)|

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0

3 years ago