Answer:
1023
Step-by-step explanation:
Positive numbers are numbers that are greater than 0.
As maximum value of numbers x and y is 4,
....(i)
So,
![x^2y^3\leq 4^2 4^3=1024](https://tex.z-dn.net/?f=x%5E2y%5E3%5Cleq%204%5E2%204%5E3%3D1024)
So, maximum value of the product
is 1024.
Also, its given that sum of numbers x and y is 5, so
...(ii)
On using equations (i) and (ii), we get
![1\leq x,1\leq y](https://tex.z-dn.net/?f=1%5Cleq%20x%2C1%5Cleq%20y)
So,
![1\leq x^2y^3](https://tex.z-dn.net/?f=1%5Cleq%20x%5E2y%5E3)
Therefore, minimum value of the product is 1.
Difference between the maximum and minimum value of the product = maximum value of the product
- minimum value of the product
=1024 - 1 = 1023
Answer:
r. should be less than equal to 11
Answer:
D) -9/4
Step-by-step explanation:
please refer to the picture I sent
Answer:
y = - 9, y = 3
Step-by-step explanation:
Calculate distance d using the distance formula
d = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%20%20%20%20%7D)
with (x₁, y₁ ) = (2, - 3) and (x₂, y₂ ) = (10, y)
d = ![\sqrt{(10-2)^2+(y+3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%2810-2%29%5E2%2B%28y%2B3%29%5E2%7D)
= ![\sqrt{8^2+(y+3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B8%5E2%2B%28y%2B3%29%5E2%7D)
Given distance between points is 10, then
= 10 ( square both sides )
64 + (y + 3)² = 100 ( subtract 64 from both sides )
(y + 3)² = 36 ( take the square root of both sides )
y + 3 = ±
= ± 6 ( subtract 3 from both sides )
y = - 3 ± 6 , thus
y = - 3 - 6 = - 9
y = - 3 + 6 = 3
John would have 52 dollars left by the fourth week.
7(dollars spent each week) x 4 ( number of weeks)=28 (spent in 4 weeks)
80 - 28 =52