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inn [45]
2 years ago
5

Equation 1: m = 8 + 2n Equation 2: 4m = 4 + 4n Step 1: −4(m) = −4(8 + 2n) 4m = 4 + 4n Step 2: −4m = −32 − 8n 4m = 4 + 4n Step 3:

−4m + 4m = −32 − 8n + 4n Step 4: 0 = −32 − 4n Step 5: n = − 8 In which step did the student first make an error?Equation 1: m = 8 + 2n Equation 2: 4m = 4 + 4n Step 1: −4(m) = −4(8 + 2n) 4m = 4 + 4n Step 2: −4m = −32 − 8n 4m = 4 + 4n Step 3: −4m + 4m = −32 − 8n + 4n Step 4: 0 = −32 − 4n Step 5: n = − 8 In which step did the student first make an error? plz help
Mathematics
1 answer:
irakobra [83]2 years ago
7 0
The error can be found in step 3. The student forgot to add four which caused him to mess up on the rest of the steps.
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Learn more on range here: brainly.com/question/2264373

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