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yan [13]
3 years ago
7

Calculate the grams of solute required to make 250 g of a 0.20% MgSO4?

Chemistry
1 answer:
Kisachek [45]3 years ago
5 0
.. it’s the answer 0.25 g MgSO4? ..
I may be wrong.
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Write the reaction from the word equation and then balence the equation
Mars2501 [29]
<h3>Answer:</h3>

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

<h3>Explanation:</h3>

We are required to write a balanced equation from the word equation;

  • Nickel reacts with lead nitrate (II) to produce nickel(III) nitrate and lead
  • The equation will be written by writing the symbols of the reactants and products.

That is;

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

We then balance the equation;

  • To balance the equation, we put appropriate coefficients on reactants and products, so that the number of atoms of each element is equal on both sides of the equation.
  • Thus, the balanced equation will be;

2Ni + 3Pb(NO₃)₂ → 2Ni(NO₃)₃ + 3Pb

4 0
3 years ago
In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally i
Mnenie [13.5K]

Answer:

A.

Carbon dioxide

Explanation:

In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally in Carbon dioxide

5 0
2 years ago
1. The following are statements about flames some of them are true while others are
hoa [83]

Answer:

i)The carbon particles are formed when the gas is not completely burnt(True)

ii)A solid or liquid must be change to gaseous state in order to make flame(TRUE)

iii)A non- luminous Bunsen flame produces has three visible regions(FALSE)

iv)The luminous Bunsen flame produces less soot than the non- luminous flame(FALSE)

v)A yellow Bunsen flame is obtained when the air holes are opened(FALSE)

vi)The luminous Bunsen flame is hotter than a non- luminous Bunsen flame(FALSE)

vii)Bunsen burner uses kerosene as a source of heat(FALSE)

Explanation:

i)When the incomplete combustion ,then CO(carbon monoxide) and C(carbon) are produced. <u>The unburnt carbon get deposited as</u><u> Soot</u>.

In complete combustion CO2(carbon dioxide) is produced.

ii)Fire, is the mixture of hot gases.Flame are result of chemical reaction between oxygen and fuel(e.g butane ,wood).Flame contain,carbon dioxide , heat ,light,steam.

iii)There are total three regions of flame in which the outer most region is the non-luminous .The non-luminous part is <u>blue(one visible region</u>) and does not emit-light.

iv) Luminous Bunsen flame produces more soot than the non- luminous flame because luminous flame contain more unburnt particles as compare to non-luminous.

luminous part has less oxygen available for complete combustion of fuel

v)When the air hole is open it means excess oxygen is supplied to the fuel.

In this case clean and luminous flame is produced.When air hole is close yellow flame is produced.

vi)Non-luminous part of flame is more hot because of complete combustion due to proper availability  of oxygen. Sometime the particle of non-luminous flame get ionize also.

vii).The bunsen burner uses Natural gas(methane) or LPG(propane and butane)as sources of heat because these are easily burnt not kerosene.

4 0
3 years ago
Mass of NaHCO3 sample (g): 1.20 g
sasho [114]

Answer: (22.98977 g Na/mol) + (1.007947 g H/mol) + (12.01078 g C/mol) + ((15.99943 g O/mol) x 3) = 84.0067 g NaHCO3/mol

9.

(1.20 g NaHCO3) / (84.0067 g NaHCO3/mol) = 0.0143 mol NaHCO3

10.

Supposing the question is asking about "how many moles" of CO2. And supposing the reaction to be something like:

NaHCO3 + H{+} = Na{+} + H2O + CO2

(0.0143 mol NaHCO3) x (1 mol CO2 / 1 mol NaHCO3) = 0.0143 mol CO2 in theory

11.

n = PV / RT = (1 atm) x (0.250 L) / ((0.0821 L atm/K mol) x (298 K)) = 0.0102 mol CO2

12.

(0.0143 mol - 0.0102 mol) / (0.0143 mol) = 0.287 = 28.7%

Explanation:

6 0
3 years ago
Two students prepare lab reports one for a chemistry class and the other for a biology class which of the following items will b
AleksandrR [38]

Answer:

the results of an investigation thank me later

Explanation:

4 0
3 years ago
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