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yan [13]
3 years ago
7

Calculate the grams of solute required to make 250 g of a 0.20% MgSO4?

Chemistry
1 answer:
Kisachek [45]3 years ago
5 0
.. it’s the answer 0.25 g MgSO4? ..
I may be wrong.
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4 years ago
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You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
3 years ago
A wave is moving towards shore with a velocity of 5.0 MS if it’s frequency is 2.5 Herz what is the wave length
EastWind [94]

Answer:

<h2>2 m</h2>

Explanation:

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\lambda =  \frac{c}{f}  \\

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c is the speed of the wave

f is the frequency

From the question

c = 5 m/s

f = 2.5 Hz

We have

\lambda =  \frac{5}{2.5}  = 2 \\

We have the final answer as

<h3>2 m </h3>

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3 years ago
What is the mass of 2.2x10^9 molecules of CO2? *​
olga55 [171]

Answer: 9.68 x 10^10 grams.

Explanation:

Given that:

Mass of CO2 = ?

Number of molecules of CO2 = 2.2x10^9 molecules

Molar mass of CO2 = ? (let unknown value be Z)

For the molar mass of CO2: Atomic mass of Carbon = 12; Oxygen = 16

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Apply the formula:

Number of molecules = (Mass of CO2 in grams/Molar mass)

2.2x10^9 molecules = Z/44g/mol

Z = 2.2x10^9 molecules x 44g/mol

Z = 9.68 x 10^10g

Thus, the mass of 2.2x10^9 molecules of CO2 is 9.68 x 10^10 grams.

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3 years ago
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