Analyze the Name of complex Compound.
T<span>etracarbonylplatinum(iv) chloride
So, there are,
4 Carbonyl groups = 4 CO = (CO)</span>₄
1 Platinum Metal = 1 Pt = Pt
Unknown Chloride atoms = ?
In complexes positive part is always named first, so the sphere containing Pt and carbonyl ligands is written first,
[Pt (CO)₄]
The charge on sphere is +4 because CO ligand is neutral, and Pt has a Oxidation state of four as written in name (IV),
So,
[Pt (CO)₄]⁴⁺
Now, in order to neutralize +4 charge we should add 4 Chloride ions, So,
[Pt (CO)₄] Cl₄
Answer:
C) low ionization energy and low electronegativity
Explanation:
The question is incomplete, the complete question is shown in the image attached to this answer
Answer:
Most similar - sulphur
least similar- gallium
Explanation:
The compound formed when hydrogen reacts with oxygen is water. The chemical formula of water is H2O.
Water is very similar to H2S which is the compound formed when hydrogen reacts with sulphur. The bonds in water and H2S are both polar covalent bonds.
However, gallium is a metal and its hydride (GaH3) is least similar to water.
Answer:
C. A question and opinions
Explanation: