1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zavuch27 [327]
3 years ago
15

The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O:

Chemistry
1 answer:
White raven [17]3 years ago
4 0

Answer:

1.5 moles

Explanation:

Given data:

Number of moles of O₂ consumed = 2.5 mol

Moles of CO₂ produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂    →     3CO₂ + 4H₂O

Now we will compare the moles of oxygen with carbon dioxide from balance chemical equation:

                             O₂             :           CO₂

                               5             :            3

                              2.5           :         3/5×2.5 = 1.5

Thus from 2.5 moles of oxygen 1.5 moles of carbon dioxide are produced.

You might be interested in
In your own words, explain the periodic law.
mote1985 [20]

    States that the properties of elements are periodic or recurring and are correlated to their atomic number.

6 0
4 years ago
A solution of CaCl 2 in water forms a mixture that is 42.0 % calcium chloride by mass. If the total mass of the mixture is 839.6
Lerok [7]

Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.

Explanation :

As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.

In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.

Now we have to determine the mass of calcium chloride for 839.6 grams of solution.

As, 100 grams of solution contains 42.0 grams of calcium chloride

So, 839.6 grams of solution contains \frac{42.0}{100}\times 839.6=352.6 grams of calcium chloride

Thus, the mass of calcium chloride used is, 352.6 grams.

Now we have to determine the mass of water.

Mass of water = Mass of solution - Mass of calcium chloride

Mass of water = 839.6 g - 352.6 g

Mass of water = 487.0 g

Thus, the mass of water used is, 487.0 grams.

6 0
3 years ago
What process is the method by which a neutral object obtains an electrical charge? A) convection B) discharge C) induction D) ra
Afina-wow [57]
The answer is C.) induction

3 0
3 years ago
Read 2 more answers
Is this correct pls answer as soon as possible
Lunna [17]

Answer: Yes

Explanation:

I just know it is.

4 0
3 years ago
Which solid from the data table would float on water?
puteri [66]

Answer:

Ther answerr is A only solid A.

Explanation:

The density of water is 1 g/cm3 so anything above that will sink,  but as you can see solid A dosnt ev en reach one./ so It will float on water. the other two are over 1 g/cm3.

<h2>If this answer helped mark it brainliest. :)</h2>

5 0
3 years ago
Other questions:
  • What happens when the electron moves from the first energy level to the second energy level?
    9·2 answers
  • According to Le Chatelier’s principle, a change in pressure affects the chemical equilibrium of the reaction system under what c
    10·2 answers
  • How many objects are in a mole of objects?
    6·1 answer
  • Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes stomach acid, primarily hcl, according to the reacti
    11·2 answers
  • Under the proper conditions, bromomethane (ch3br) will react with potassium hydroxide (koh) to form _____ and a salt. methanol (
    12·2 answers
  • In a chemical equation, the arrow
    6·2 answers
  • Which process would most likely be employed to separate a mixture of sand and water?
    9·2 answers
  • At which point is potential energy greatest
    12·2 answers
  • Which statement is TRUE according to the kinetic molecular theory? Which statement is TRUE according to the kinetic molecular th
    13·1 answer
  • Help Tell me the answer.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!