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zavuch27 [327]
3 years ago
15

The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O:

Chemistry
1 answer:
White raven [17]3 years ago
4 0

Answer:

1.5 moles

Explanation:

Given data:

Number of moles of O₂ consumed = 2.5 mol

Moles of CO₂ produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂    →     3CO₂ + 4H₂O

Now we will compare the moles of oxygen with carbon dioxide from balance chemical equation:

                             O₂             :           CO₂

                               5             :            3

                              2.5           :         3/5×2.5 = 1.5

Thus from 2.5 moles of oxygen 1.5 moles of carbon dioxide are produced.

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Balance the following equation:
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Answer: a) 2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

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Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

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K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O

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When 1 mole of I_2 is produced, 1 mole of SO_2 is produced.

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