The length of pencil A is 5 cm
<em><u>Solution:</u></em>
Let the length of pencil A be "x"
Let the length of pencil B be "y"
Let the length of pencil C be "z"
<em><u>The total length of pencils A, B and C is 29 cm</u></em>
Therefore,
length of pencil A + length of pencil B + length of pencil C = 29
x + y + z = 29 ------------ eqn 1
<em><u>Pencil A is 11 cm shorter then pencil B</u></em>
x = y - 11 ------- eqn 2
<em><u>Pencil B is twice as long a pencil C</u></em>
y = 2z
------ eqn 3
<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

<em><u>Substitute y = 16 in eqn 2</u></em>
x = 16 - 11
x = 5
Thus length of pencil A is 5 cm
Answer:
- 3
Step-by-step explanation:
let n be the number , then
3n + 4 = n - 2 ( subtract n from both sides )
2n + 4 = - 2 ( subtract 4 from both sides )
2n = - 6 ( divide both sides by 2 )
n = - 3
The number is - 3
Answer:
4
Step-by-step explanation:
2×2=4
6÷2=3
1×2=2
8÷2=4
3×2=6
?÷2=2
2×2=4
all you have to do is add up all the sides and your answer will be 21 cm
Answer:
7, 7, 60, 60, 60
Step-by-step explanation:
When you draw the circles thhey all hhave radius AB so AB=AC=BC =7
and since all sides are congruent you have a equilateral treangle so all angles are equal to 180/3=60