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maxonik [38]
3 years ago
9

which of the following small bodies are the hardest to tell apart because they are made of similar materials ? A . dwarf planets

and comets. . b. asteroids and comets . . c. comets and metoroids . . d. asteroids and meteroids
Physics
2 answers:
grandymaker [24]3 years ago
8 0
Option D is right that is asteroids and meteroids.
Svetllana [295]3 years ago
6 0

Answer: d. asteroids and meteoroids

Explanation:

A comet is made of rocks and frozen gases and is found in the outskirts of the solar system. A dwarf planet is large in size and round in shape as compared to an asteroid and has rocky composition.

Asteroids and meteoroids are rocky in composition and have irregular shape and size. Majority of the asteroids are found in between the orbits of Mars and Jupiter. These are thought to form from an unformed planet. Meteoroids are debris of planets and comets. Thus, it is difficult to distinguish between the two because of the similar materials.

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Points a and b lie in a region where the y-component of the electric field is Ey=α+β/y2. The constants in this expression have t
Drupady [299]

Answer:

V_{a} - V_{b} = 89.3

Explanation:

The electric potential is defined by

         V_{b} - V_{a} = - ∫ E .ds

In this case the electric field is in the direction and the points (ds) are also in the direction and therefore the angle is zero and the scalar product is reduced to the algebraic product.

         V_{b} - V_{a} = - ∫ E ds

We substitute

         V_{b} - V_{a} = - ∫ (α + β/ y²) dy

We integrate

          V_{b} - V_{a} = - α y + β / y

We evaluate between the lower limit A  2 cm = 0.02 m and the upper limit B 3 cm = 0.03 m

           V_{b} - V_{a} = - α (0.03 - 0.02) + β (1 / 0.03 - 1 / 0.02)

            V_{b} - V_{a} = - 600 0.01 + 5 (-16.67) = -6 - 83.33

            V_{b} - V_{a} = - 89.3 V

As they ask us the reverse case

             V_{b} - V_{a} = - V_{b} - V_{a}

             V_{a} - V_{b} = 89.3

3 0
3 years ago
Semi-trailer trucks have an odometer on one hub of a trailer wheel. The hub is weighted so that it does not rotate, but it conta
shtirl [24]

Answer:

1020 km

Explanation:

A complete rotation of the wheel equals a distance of 1 circumference.

The circumference is

C = \pi d

where <em>d</em> is the diameter of the wheel.

300,000 rotations = 300000\pi d = 300000\times\pi\times1.08\text{ m} = 1017876.0\ldots\text{ m}

In kilometers, this is = 1017876/1000 km = 1020 km

6 0
3 years ago
If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?
Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

y=y_{o}+V_{oy}t-\frac{g}{2}t^{2} (1)

Where:

y=0 is the final height of the ball

y_{o}=h is the initial height of the ball

V_{oy}=V_{o}sin(0\°)=0 is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

t=0.5 s is the time at which the ball lands

g=9.8 m/s^{2} is the acceleration due gravity

So, with these conditions the equation is rewritten as:

h=\frac{g}{2}t^{2} (2)

h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2} (3)

Finally:

h=1.22 m

4 0
2 years ago
What is the efficiency (w/qh) of an ideal carnot heat engine operating between a hot region at t= 400 k and a cold one at t= 300
Vinvika [58]
The efficiency of an ideal Carnot heat engine can be written as:
\eta = 1-  \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the temperature of the cold region
T_{hot} is the temperature of the hot region

For the engine in our problem, we have T_{cold}=300 K and T_{hot}=400 K, so the efficiency is
\eta= 1 - \frac{300 K}{400 K}=0.25
4 0
2 years ago
Hey guys! Am I right? Thanks!
worty [1.4K]

Answer:

the correct answer is reduce friction

5 0
2 years ago
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