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il63 [147K]
2 years ago
5

In Thomson’s experiment, why was the glowing beam repelled by a negatively charged plate?

Physics
1 answer:
Svetllana [295]2 years ago
5 0

The glowing beam was repelled by a negatively charged plate because they were negatively charged

<h3>What are the nature of charges?</h3>

The nature of charges refers to the properties of charges.

There are two types of charges:

  • negative charges
  • positive charges

The law of electricity states that opposite charges attract whereas like charges repel.

Therefor, in Thomson’s experiment, the glowing beam was repelled by a negatively charged plate because they were negatively charged

In conclusion, like charges repel while opposite charges attract.

Learn more about charges at: brainly.com/question/12781208

#SPJ1

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3 years ago
The normal force always points ____ to the two surfaces in contact.
shepuryov [24]

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3 years ago
A package is dropped from a helicopter that is moving upward at15m/s. If it takes 8.0 sec before the package strikes the ground,
Rainbow [258]

Answer:

313.6 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 8 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

The height at which the package was dropped can be obtained as follow:

h = ½gt²

h = ½ × 9.8 × 8²

h = 4.9 × 64

h = 313.6 m

Thus, the package was at a height of 313.6 m when it was dropped.

7 0
3 years ago
A 25.0 kg projectile is fired by accelerating it with an electromagnetic rail gun on the earth's surface. the rail makes a 30.0
stich3 [128]

(a)

The work done on the projectile is 9375 joule.

The work on the projectile is calculated as

W=F×d

=1250×7.5

=9375 joule

(b)

The speed of the projectile after 7.5 m is 27.38 m/s

First we need to find out the acceleration of the projectile

F=m×a

1250=25×a

a=50 m/s^{2}

Now the velocity of the projectile after 7.5 m is calculated as

v^2=u^2+2a×s

v^2=0+2×50*7.5

v=27.38 m/s

8 0
3 years ago
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