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kiruha [24]
3 years ago
12

A student gives a 5.0 kg box a brief push causing the box to move with an initial speed of 8.0 m/s along a rough surface. The bo

x experiences a friction force of 30 N as it slows to a stop. How long does it take the box to stop?
Physics
1 answer:
WITCHER [35]3 years ago
5 0

Answer:

The time taken to stop the box equals 1.33 seconds.

Explanation:

Since frictional force always acts opposite to the motion of the box we can find the acceleration that the force produces using newton's second law of motion as shown below:

F=mass\times acceleration\\\\\therefore acceleration=\frac{Force}{mass}

Given mass of box = 5.0 kg

Frictional force = 30 N

thus

acceleration=\frac{30}{5}=6m/s^{2}

Now to find the time that the box requires to stop can be calculated by first equation of kinematics

The box will stop when it's final velocity becomes zero

v=u+at\\\\0=8-6\times t\\\\\therefore t=\frac{8}{6}=4/3seconds

Here acceleration is taken as negative since it opposes the motion of the box since frictional force always opposes motion.

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

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y = (m₁y₁ + m₂y₂ + m₃y₃) / M       ----------------(ii)

Where;

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From the question;

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