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Andre45 [30]
3 years ago
11

When a steady direct current flows through a coil, the only opposition to the flow of current is the resistance of the wire from

which the coil is made.
Physics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

True

Explanation:

This is true statement because in DC circuit there is only resistance which comes into play of opposition of current.

In DC circuit there is no role of frequency in if there is no frequency then there will no inductive reactance and no capacitive reactance to oppose the current flow

So in DC circuit only resistance is responsible to oppose the flow of current

So this is a true statement

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A mixed cost contains Select one:
-Dominant- [34]

A mixed cost contains a variable element and a fixed element.

Option a

<u>Explanation:</u>

Mixed costs are those costs that has both variable and fixed component. Example: operating cost of a machinery includes fixed costs that cannot be changed with other variable costs like fuel, insurance, depreciation, etc.

It is also named as semi-variable costs. And the formula to calculate mixed cost is as follows,

y=a+b x

where,

  • y is the "total cost "
  • a is the "fixed cost per period"
  • b is the "variable rate per unit of activity"
  • x is the "number of units of activity"
3 0
3 years ago
Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

3 0
3 years ago
An automobile engine delivers 55.0 hp. How much time will it take for the engine to do 6.22 × 105 J of work? One horsepower is e
Gennadij [26K]

Answer:

15.2 s

Explanation:

Convert hp to W:

55.0 hp × 746 W/hp = 41,030 W

Power = energy / time

41030 W = 6.22×10⁵ J / t

t = 15.2 s

8 0
3 years ago
What is the approximate initial height of the counterweight?
BabaBlast [244]

Answer: I don't know this one but I'm just came here for points

Explanation:

5 0
3 years ago
A box with a mass of 40 kg sits at rest on a frictionless tile floor. with your foot, you apply a 20 N force in a horizontal dir
Grace [21]

Answer:

0.5 m/s²

Explanation:

according to Newton's second law, we are goven a relationship between force, mass and acceleration, with the formula:

F = m×a

F for force

m for mass

a for acceleration

we use the given data and get:

20 = 40×a

we find a=20/40=0.5m/s²

4 0
2 years ago
Read 2 more answers
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