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Andre45 [30]
3 years ago
11

When a steady direct current flows through a coil, the only opposition to the flow of current is the resistance of the wire from

which the coil is made.
Physics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

True

Explanation:

This is true statement because in DC circuit there is only resistance which comes into play of opposition of current.

In DC circuit there is no role of frequency in if there is no frequency then there will no inductive reactance and no capacitive reactance to oppose the current flow

So in DC circuit only resistance is responsible to oppose the flow of current

So this is a true statement

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In a basketball game, a player shoots a jump shot. What force actually causes the player to jump into the air? Question 3 option
Julli [10]

Option B is the correct answer.

In a basketball game, a player shoots a jump shot then the floor pushes up on the player.

<h3>Newton's Third Law</h3>

Newton's third law states that when two bodies interact with each other, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

In the given situation, a player shoots a jump shot. It means that the player pushes the floor downward direction.

Newton's third law is applicable in this situation where the player pushes the floor downward direction, at the same time the floor pushes the player upward. The amount of force applied to the floor by the player is equal in magnitude and opposite in direction as compared to the force applied to the player by the floor.

Hence the option B is the correct answer.

To know more about Newton's third law, follow the link given below.

brainly.com/question/974124.

6 0
3 years ago
A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius r. Which variable does not affect the
Maru [420]

Answer:

The radius r of the metal sphere.

Explanation:

From Gauss's law we know that for a spherical charge distribution with charge Q, the electrical field at distance R from the center of the sphere is given by

E=\frac{Q}{4\pi \epsilon_oR^2}

What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance R feels the force as if all the charge Q were sitting at the center of the sphere.

This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.

6 0
3 years ago
In an RL series circuit, an inductor of 3.54 H and a resistor of 7.76 Ω are connected to a 26.6 V battery. The switch of the cir
podryga [215]

Answer:

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So  current i=\frac{V}{R}=\frac{26.6}{7.76}=3.427Amp

Now energy stored in inductor E=\frac{1}{2}Li^2=\frac{1}{2}\times 3.54\times 3.427^2=20.797J

So energy stored in inductor will be 20.797 J

4 0
4 years ago
Which statement best describes a solid?
aksik [14]
Fixed shape and fixed volume

6 0
3 years ago
Read 2 more answers
In a 120-volt circuit having a resistance of 12 ohms, the power W in watts when a current I is flowing through is given by W=120
Mrac [35]

Answer:

maximum power = 300 W

Explanation:

Ohm's law: Ohm's law state that the current flowing through a metallic conductor, is directly proportional to the potential difference applied across its end. mathematically it is expressed as,

V = IR............. Equation 1

Where V = potential difference, I = current, R = Resistance of the conductor.

If the power flowing through is gives as

W = 120I - 12I² ..................... Equation 2

To get the maximum power we differentiate of equation 2  and equate to zero

dW/dt = 0

120 - 24l = 0........................... equation 3

Making I the subject of the equation,

I = 120/24 = 5 A.

Suubstituting the value of I into Equation 2

W = 120 (5) - 12(5)²

W = 600 - 300

W = 300 W.

Therefore maximum power = 300 W

5 0
4 years ago
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