Answer:
K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹
Explanation:
Rate of flow of heat through a material is given by the following expression
where Q is amount of heat flowing in time t through area A and a medium of thickness d having two faces at temperature difference δT . K is thermal conductivity of the medium .
Here Q = 3.34 x 10⁶/6 , t = 24 x 60 x 60 = 86400 s , A = .332 X .332 = .0110224 m² , δT = 104.7
Put these values here
K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹
3 as a single number is considered a sf
C because of galvination is sized
Answer:
Check Explanation.
The two statements given aren't true.
Explanation:
Although the question seems incomplete, I will address the concept of energy transfer during a wave's propagation.
The particles involved in wave's propagation move back and forth perpendicularly to the way the wave is moving, but do not move (at least, no significant movement is noticeable) in the direction of the wave. The particles ‘participate’ in the wave propagation by bumping into one another and transferring energy. This is exactly why energy can be transferred, although the average position of the particles doesn’t change.
So, the particles of the medium do not absorb energy from the atmosphere and do not significantly move from one location to another.
Hope this Helps!!!
