The increase in temperature of the metal hammer is 0.028 ⁰C.
The given parameters:
- <em>mass of the metal hammer, m = 1.0 kg</em>
- <em>speed of the hammer, v = 5.0 m/s</em>
- <em>specific heat capacity of iron, 450 J/kg⁰C</em>
The increase in temperature of the metal hammer is calculated as follows;
where;
<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>
<em />
Assuming the metal hammer is iron, c = 450 J/kg⁰C
Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
It depends on the kind of soda can
Answer:
Explanation:
Given that,
Frequency f = 5 kHz = 5000Hz
Voltage V=45V
Current In inductor I = 65mA
I = 65 × 10^-3 = 0.065A
We want to find inductance L
We know that the reactive inductance cam be given as
XL = 2πFL
Where
XL is reactive inductance
F is frequency
L is inductance
Then,
L = XL/2πF
From ohms law
V = IR
We can calculate the receive reactance of the inductor
V = I•XL
Then, XL = V/I
XL = 45/0.065
XL = 692.31 ohms
Then,
L = XL/2πF
L = 692.31/(2π×5000)
L = 0.02204 H
Then, L = 22.04 mH
The inductance of the inductor is 22.04mH
Answer:
Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.
