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Scrat [10]
3 years ago
13

A pulse traveled the length of a stretched spring.

Physics
2 answers:
aksik [14]3 years ago
8 0

Answer: The correct answer is energy only.

Explanation:

Wave is a disturbance which carries energy from one particle to another particle. It is a continuous disturbance.

Pulse is a single disturbance. It is non repeating single bump. It carries energy only. For example, a person is holding one end of the rope. He is moving that end. The pulse will create through the rope.

A pulse travels the length of a stretched spring. The pulse transfers the energy only.

Therefore, the correct option is (1).

melomori [17]3 years ago
8 0
<span>So we want to know to what is the pulse transformed that traveled the length of a stretched spring. So a pulse is a part of a mechanical wave, and mechanical waves are energy transfer trough some medium, in this case a stretched spring. So the correct answer is (1) energy. The pulse cant be transferred into mass. </span>
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Two metra trains approach each other on separate but parallel tracks. one has a speed of 90 km/hr, the other 80 km/hr. initially
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The trains take <u>57.4 s</u> to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

v_A=90 km/h\\ v_B=-80 km/h

The relative velocity of the train A with respect to B is given by,

v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

t= \frac{d}{v_A_B}

Substitute 2.71 km for d and 170 km/h for v_A_B

t= \frac{d}{v_A_B}\\ =\frac{2.71 km}{170 km/h} \\ =0.01594 h

Express the time in seconds.

t=(0.01594h)(3600s/h)=57.39s

Thus, the trains cross each other in <u>57.4 s</u>.

6 0
2 years ago
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Answer:

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for this exercise in geometric optics let's use the equation of the constructor

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          \frac{1}{f_1} = \frac{1}{q}

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2) for an object located at p = 25 cm

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2)     P₂ = 1 /0.16667

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