A mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. If the mass of the object is 0.20 kg and the sp
1 answer:
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Answer:
The third particle should be at 0.0743 m from the origin on the negative x-axis.
Explanation:
Let's assume that the third charge is on the negative x-axis. So we have:
We know that the electric field is:
Where:
- k is the Coulomb constant
- q is the charge
- r is the distance from the charge to the point
So, we have:
Let's solve it for r(3).
Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.
I hope it helps you!
Complete Question
A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?
Answer:
The values is
Explanation:
From the question we are told that
The diameter is
The charge is
The distance from the center is
Generally the radius is mathematically represented as
=>
=>
Generally electric field is mathematically represented as
substituting values