Answer:

Explanation:
We can find the resistance of the wire by using Ohm's law:

where
V is the voltage applied
R is the resistance
I is the current
In this problem, we know I = 6 A and V = 68 V, so we can re-arrange the equation to find the resistance of the wire:

Hi!
The correct answer would be: the width of I-bands
The sacromere is the smallest contractile unit of striated muscles. These units comprise of filaments (fibrous proteins) that, upon muscle contraction or relaxation, slide past each other. The sacromere consists of thick filaments (myosin) and thin filaments (actin).
<em>Refer to the attached picture to clearly see the structure of a sacromere.</em>
<u>When a sacromere contracts, a series of changes take place which include:</u>
<em>- Shortening of I band, and consequently the H zone</em>
<em>- The A line remains unchanged</em>
<em>- Z lines come closer to each other (and this is due to the shortening of the I bands) </em>
The only changes that take place occur in the zones/areas in the sacromere (as mentioned), not in the filaments (actin and myosin) that make the up the sacromere; hence all other options are wrong.
Hope this helps!
Answer:
458.33 ft
Explanation:
We are given that
Wavelength of of an x- ray photon=1 in
Wavelength of of an x- ray photon==
ft
1 in=
feet
We have to find the length of line (in feet) drawn by you to represent the wavelength of visible light.
According to question
Wavelength of visible light=
ft
Wavelength of visible light
ft
Wavelength of visible light=458.33 ft
Hence, the 458.33 ft line must drawn by you to represent the wavelength of visible light.
Answer:
c) 100,000 m/s
Explanation:
You need to take the same wave length from the top graph and bottom one, so let's take half a wave length then in the top one that is 0.005, but in the bottom one it's 2000/4 = 500 because they are smaller and there are 4 half waves before you get to 2000, whereas in the top one there is 1 half wave before you get to 0.005 on the graph.
Now use speed = distance / time
speed = 500 / 0.005 = 100 000 m/s
Answer:
F = 85.24 N
T = 30.84 N
Explanation:
The parameters given are
Mass of crates = m₁ = 3 kg and m₂ = 5 kg
Component of masses acting along the plane = mgsin(θ)
Which gives;
F - (3×9.81×sin(30) + 10 + 5×9.81×sin(30) + 17) = m×a
So that we have;
2 = (F - 66.24)(3 + 5)
F = 16 + 66.24 = 85.24 N
The tension T between the crates = F × m₁/(m₁+m₂) = 85.24 × 3/(3+5) = 30.84 N