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3 years ago

14

Coherent light with wavelength 599 nm passes through two very narrow slits with separation of 20 μm, and the interference patter

n is observed on a screen located at a distance of 3.0 m from the slits. Where will the second order dark fringe above the center of central bright fringe will form?

1 answer:

goblinko [34]3 years ago

7 0

Answer:

134.77 mm

Explanation:

Wave length of light λ = 599 x 10⁻⁹ m

Slit separation d = 20 x 10⁻⁶ m

Screen distance D = 3 m

Distance of second dark fringe from centre

= 1.5 x λ D / d

Putting the values given above

distance = $\frac{1.5\times599\times10^{-9}\times 3}{20\times10^{-6}}$

= 134.77 x 10⁻³ m

= 134.77 mm.

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A 65-kg ice skater stands facing a wall with his arms bent and then pushes away from the wall by straightening his arms. At the

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Our values can be defined like this,

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2 years ago

A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

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A) 750 m

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2 years ago

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olya-2409 [2.1K]

Answer:

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2 years ago