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Debora [2.8K]
3 years ago
5

A bullet with a mass mb=11.5 g is fired into a block of wood at velocity ????b=265 m/s. The block is attached to a spring that h

as a spring constant ???? of 205 N/m. The block and bullet continue to move, compressing the spring by 35.0 cm before the whole system momentarily comes to a stop. Assuming that the surface on which the block is resting is frictionless, determine the mass of the wooden block. From left to right, a bullet of mass m subscript b has a velocity of v subscript b with a velocity vector pointing directly to the right. The vector points toward a block that is attached on its right face to a spring of force constant k. The other end of the spring is attached to a fixed, vertical surface. mass of wooden block: ____________
Physics
1 answer:
Alla [95]3 years ago
6 0

Answer:

m=0.496 kg

Explanation:

Knowing the potential energy in the spring is equal to the initial kinetic energy  so:

F_s=E_K

\frac{1}{2}*K*x^2=\frac{1}{2}*m_b*v_f^2

\frac{1}{2}*205n/m*(0.35m)^2=\frac{1}{2}*m_b*v_f^2

Now using the conservation of momentum

P_i=P_f

m_b*v_i=(m_b+m_w)*v_f

11.5x10^3kg*265m/s=(11.5x10^3kg+m)*v_f

v_f=\frac{3.0475 kg*m/s}{(11.5x1063kg+m)}

Replacing in initial equation so:

12.5556J=\frac{1}{2}*11.5x10^3kg*(\frac{3.0475 kg*m/s}{11.5x10^3kg+m})^2

Solve to m

m=\frac{6.23}{12.556}

m=0.496 kg

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The acceleration due to gravity on the surface of Mars is about one-third the acceleration due to gravity on Earth’s surface.
aksik [14]

Answer:

one-third of its weight on Earth's surface

Explanation:

Weight of an object is = W = m*g

Gravity on Earth = g₁ = 9.8 m/s

Gravity on Mars = g₂ = \frac{1}{3} g₁

Weight of probe on earth = w₁ = m * g₁

Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )

As g₂ = g₁/3 --------- ( 2 )

Put equation (2) in equation (1)

so

Weight of probe on Mars = w₂ = m * g₁ /3

Weight of probe on Mars = \frac{1}{3}  m * g₁ = \frac{1}{3} w₁

⇒Weight of probe on Mars =\frac{1}{3} Weight of probe on earth

6 0
4 years ago
Force of 10N down,10N to the right,and 5N to the left are acting on a ball .it acceleration horizontally to the right.what other
denpristay [2]

Answer:

A 10 N force pointing up

Explanation:

If the net acceleration of the object is horizontal pointing to the right, that means that all vertical forces must have canceled out, and the only ones "unbalanced" are the horizontal ones (10 N to the right minus 5 N to the left giving a net force of 5 N to the right).

Since they mentioned only one vertical force pointing down (10 N), there must be another one of same magnitude but pointing in opposite direction (up).

Then there must also be a 10 N force pointing up acting on the object.

3 0
3 years ago
In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met
Molodets [167]

Answer:

The number of electrons emitted from the metal per second increases.

Explanation:

The photoelectric effect can be explained by thinking the incident light as made of many photons, each carrying an energy of

E=hf

where h is the Planck constant and f is the light frequency. A photoelectron is extracted from the metal if the energy of the incoming photon, which hits the electron and gives all its energy, is at least equal to the work function of the metal, \phi. Moreover, each photon of the incident light hits only one electron in the metal.

Given these premises, we can analyze each statement:

The work function of the metal decreases.   --> FALSE. The work function is just the energy needed to extract photoelectrons from the metal: so, it depends only on the properties of the metal, and not on the intensity of the incident light.

The number of electrons emitted from the metal per second increases.   --> TRUE. The intensity of the incident light is proportional to the number of photons contained in the light: so, the higher the intensity, the larger the number of photons that hit the electrons in the metal, the larger the number of electrons emitted.

The maximum speed of the emitted electrons increases.   --> FALSE. The energy of the electrons emitted depends ONLY on the energy of the incoming photon, so it depends only on the frequency of the photon, not on the number of photon (intensity). In fact, only 1 photon at time hits 1 electron, so the intensity of the light does not affect the energy of the electrons (and so, it does not affect their speed)

The stopping potential increases. --> FALSE. The stopping potential is the potential needed to stop the electrons in the metal preventing them to escape the metal: this depends only on the energy of the electron, which does not depend on the intensity of the light, but only on its frequency.

4 0
3 years ago
Astronomers arrange the stars into groups called spectral classes (or types) according to the kinds of lines they find in their
MArishka [77]

Answer:

Temperature

Explanation:

The spectral types are:

O, B, A, F, G, K, M

They are arranged in order from the highest temperature to the coolest temperature

8 0
3 years ago
What is true of a mechanical wave? @3.2.P.B5 @1
statuscvo [17]
I think it is B. Mechanical waves carry energy through a medium. 
7 0
3 years ago
Read 2 more answers
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