Answer:
81.86%
Step-by-step explanation:
We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.
First of all we will find z-score using z-score formula.
Now let us find z-score for 86.
Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.
Using normal distribution table we will get,

We will use formula
to find the probability to find that a normal variable lies between two values.
Upon substituting our given values in above formula we will get,


Upon converting 0.81859 to percentage we will get

Therefore, 81.86% of final exam score will be between 68 and 86.
Given :
7x is an odd integer.
To Find :
The next odd integer as an algebraic expression in x.
Solution :
All positive integers are :
1 , 2 , 3 , 4 , 5 , ......
From the above series we noticed that every other odd number is 2 more than the previous one.
So , 7x is an odd number.
Therefore, next odd number is 7x + 2.
Hence, this is the required solution.
Answer:
(x - 6)^2 + (y + 2)^2 = (x - 2)^2 or -8 x + y^2 + 4 y + 36 = 0
Step-by-step explanation: