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3 years ago

In the lab, you analyze a substance to consist of 52% zinc, 9.6% carbon, and 38.4% oxygen. what is the empirical formula?

Chemistry

1 answer:

nevsk [136]3 years ago

6 0

Zn= 0.795 C= 0.799 O= 2.4
EF = ZnCO3

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Answer ASAP pls

Komok [63]

Answer:

wavelengths

Explanation:

4 0

2 years ago

What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?

leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0

3 years ago

What substance is reduced in the reaction 2Fe 2+ + CI2 = 2Fe 3+ + 2CI- ?

atroni [7]

Answer:

$Cl_{2}$ is reduced in the reaction

Explanation:

The given reaction is

$2Fe^{2+}+Cl_{2} \to 2Fe^{3+}+2Cl^{-}$

The oxidation number of $Fe$ is changed from $+2\, \to \, +3$

$Fe^{2+} \to Fe^{3+}+e^{-}$

And The oxidation number of $Cl$ is changed from $0\, \to \, -1$

$Cl_{2}^{0} + 2e^{-} \to 2Cl^{-}$

Hence, $Fe^{2+}$ is oxidized and $Cl_{2}$ is reduced

5 0

4 years ago

What is the atomic number of L? <br><br> 12<br><br> 14<br><br> 2<br><br> 8

lisov135 [29]

Answer:

12.

1 + 2 + 1 = 4 + 1 + 2 + 1 + 4 = 12 = 4 + 1 + 2 + 1 + 4 = 1 + 2 + 1

5 0

3 years ago

a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new press

goldfiish [28.3K]

<h2>Hello!</h2>

The answer is: 4.77atm

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

$\frac{P}{T}=k$

<em>P</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

We also have the following equation:

$\frac{P1}{T1}=\frac{P2}{T2}$

Where:

$P2=\frac{P1*T2}{T1}=\frac{317kPa*235K}{154K}=483.73kPa$

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

$1kPa=0.009869atm$

Then,

$483.733kPa*\frac{0.009869atm}{1kPa}=4.77atm$

Have a nice day!

8 0

4 years ago