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vladimir1956 [14]
3 years ago
9

______________________ produce evidence that helps to answer important questions or could also lead to new questions. A.investig

ations B. theories C.laws D. none of the above
Chemistry
2 answers:
V125BC [204]3 years ago
7 0

Answer: A. Investigation

Explanation:

siniylev [52]3 years ago
6 0

Answer:

B

Explanation:

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On July 8th, I will be 8.51472x10^8 seconds old. How old will I be in years? (Assume 365 days in a year.) Group of answer choice
KatRina [158]

Answer:

26.98

almost 27 years

5 0
3 years ago
How many joules are needed to melt 50 g of ice at 0°C?
Alexeev081 [22]

Answer:

You need the Delta H fusion for water. Multiply that by 50 grams. Then multiply 50 g x 4.184 x 65 to get joules to raise water to 65 degrees. Add these values together to get total joules.

Explanation:

6 0
3 years ago
Which quantum number distinguishes the different shapes of the orbitals?
UkoKoshka [18]
The four quantum numbers are:
principle quantum number: this number describes the energy of orbitals. It describes the most probable distance between the electron and the nucleus.
angular quantum number: this number describes the shape of orbitals, and thus, describes the angular distribution.
magnetic quantum number: this number describes the number of orbitals and how they are oriented within the subshell
spin quantum number: this number determines the direction of the spin of the electron.

Based on the above, the quantum number that distinguishes the different shapes of the orbitals is the angular quantum number
7 0
3 years ago
Chlorine atoms react with methane, forming HCl and CH3. The rate constant for the reaction was determined to be 3.600×107 at 278
Ratling [72]

<u>Answer:</u> The activation energy for the reaction is 40.143 kJ/mol

<u>Explanation:</u>

To calculate activation energy of the reaction, we use Arrhenius equation for two different temperatures, which is:

\ln(\frac{K_{317K}}{K_{278K}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{317K} = equilibrium constant at 317 K = 3.050\times 10^{8}M^{-1}s^{-1}

K_{278K} = equilibrium constant at 278 K = 3.600\times 10^{7}M^{-1}s^{-1}

E_a = Activation energy = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 278 K

T_2 = final temperature = 317 K

Putting values in above equation, we get:

\ln(\frac{3.050\times 10^8}{3.600\times 10^{7}})=\frac{E_a}{8.314J/mol.K}[\frac{1}{278}-\frac{1}{317}]\\\\E_a=40143.3J/mol=40.143kJ/mol

Hence, the activation energy for the reaction is 40.143 kJ/mol

8 0
3 years ago
Fractional distilation of liquid air usually produces nitrogen and oxygen as major products . Substance used to remove carbon iv
Nastasia [14]

Answer:

Caustic soda

Explanation:

The fractional distillation of air is carried out on liquid air. Before air is liquified, the carbon dioxide content of air is removed using caustic soda. The air is then compressed to a pressure of about 200 atm, sudden expansion of the gas leads to cooling. The process continues until air becomes liquid at  -200°C.

Fractional distillation of liquid air usually produces nitrogen and oxygen as major products. nitrogen in obtained first since it has a lower boiling point than oxygen. The gases are then dried, compressed and stored in cylinders.

5 0
3 years ago
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