I looked up what is the molecular formula for Phosphine and got this: PH3
Hope this helps! Let my know if this was correct.
2.168 L of air will leave the container as it warms
<h3>Further explanation</h3>
Given
V₁=2.05 L
T₁ = 5 + 273 = 278 K
T₂ = 21 + 273 = 294 K
Required
Volume of air
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
![\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7BV_1%7D%7BT_1%7D%3D%5Cdfrac%7BV_2%7D%7BT_2%7D)
Input the value :
V₂=(V₁.T₂)/T₁
V₂=(2.05 x 294)/278
V₂=2.168 L
Method:
1) Find the atomic number in a periodic table: the number of electrons equal the atomic number
2) Use Aufbau rule
Element atomic number electron configuration
<span>
P 15 1s2 2s2 2p6 3s2 3p3
Ca 20 </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2
</span>Si 14</span><span> 1s2 2s2 2p6 3s2 3p2
S 16</span><span><span> 1s2 2s2 2p6 3s2 3p4
</span>Ga 31. </span><span><span> 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span> </span>
Answer:
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The conversion of 2 - butanol to 2 - nitrobutane involves conversion of 2 butanol to 2 - bromobutane and subsequently to 2 - nitrobutane.
In order to convert 2 - butanol to 2 - nitrobutane, an SN2 reaction is first carried out in which 2 - butanol is converted to 2 - bromobutane. This reaction proceeds with inversion of configuration at the chiral carbon as expected.
This product is subsequently reacted with silver nitrite in ethanol to yield 2 - nitrobutane along side silver bromide. Some alkyl nitrite is also produced as a by product. The components of the mixture are separated by fractional distillation. The scheme of the reaction is shown in the image attached to this answer. This reaction is only applied to primary and secondary alkyl halides.
Learn more: brainly.com/question/10079361