The balanced equation of NaOH and H2SO4 would be:
2NaOH + H2SO4 = Na2SO4 + 2H2O
To determine the concentration of NaOH, we first find the moles of NaOH used in the reaction. We start with the the concentration and volume of H2SO4. We do as follows:
2.00 M H2SO4 ( 0.25 L ) = 0.5 mol H2SO4
0.5 mol H2SO4 ( 2 mol NaOH / 1 mol H2SO4) = 1 mol NaOH
Molarity = 1 mol NaOH / 2.00 L NaOH solution = 0.5 M NaOH solution
Answer:
ability to react with other elements
Explanation:
Answer:
1.36 K
Explanation:
We have the following data:
The heat gained by HCl is calculated as:
heat = m x Sh x ΔT
where m is the mass of HCl (100.0 g), Sh is the specific heat of HCl (4.017 J/K.g) and ΔT is the change in temperature. We introduce the data in the mathematical expression to calculate ΔT as follows:
ΔT = heat/(m x Sh) = 546.5 J/(100.0 g x 4.017 J/K.g) = 1.36 K
Therefore, the change in temperature is 1.36 K.
Answer:
7.055 atm
Explanation:
T = (273 + 37)K = <em>310K</em>
The ideal gas constant =<em> 0.0821</em>atm.L/mol.K
Concentration = (0.90g)*(1mol/58.4g/0.100mL) = 0.154mol/L
Molar mass= Concentration*i
Osmotic pressure = Molar mass *the ideal gas constant*T
OP = (0.154)*(1.8)*(0.0821)*(310) = 7.055 atm
You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
