Question 4................................(2)

REASONING IN ALGEBRA AND GEOMETRY Fill in the reason that justifies each step

pantera1 [17]

9514 1404 393

Answer:

1a. multiplication property of equality

1b. distributive property

1c. subtraction property of equality

1d. division property of equality

2a. distributive property

2b. addition property of equality

2c. division property of equality

Step-by-step explanation:

The properties that let you do the same thing to both sides of an equation are the properties of equality. These are usually given an additional qualifier according to the operation being performed: addition property ..., subtraction property ..., multiplication property ..., division property .... The property that lets you add or eliminate parentheses is the distributive property (of multiplication over addition).

To answer these questions, you need to compare each line to the previous to see what operation was performed. It will generally be use of one of the properties described above, or "simplification," in which like terms are combined.

1a. both sides are multiplied by 3: multiplication property of equality

1b. parentheses are eliminated: distributive property

1c. 18 is subtracted from both sides: subtraction property of equality

1d. both sides are divided by 2: division property of equality

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2a. parentheses are eliminated: distributive property

2b. 24 is added to both sides: addition property of equality

2c. both sides are divided by 2: division property of equality

5 0

3 years ago

Suppose $1,000 is borrowed for one year at 8% simple interest. How much is due at the end of the year to

AleksAgata [21]

Answer:

you will be bankrupt simple!

6 0

3 years ago

Read 2 more answers

Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.

lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is tested if the mean lifetime is not greater than 220,000 miles, that is:

$H_0: \mu \leq 220000$

At the alternative hypothesis, it is tested if the mean lifetime is greater than 220,000 miles, that is:

$H_1: \mu > 220000$ .

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem:

$\overline{x} = 226450, \mu = 220000, s = 11500, n = 23$

Then, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}$

$t = 2.69$

We have a right-tailed test(test if the mean is greater than a value), with t = 2.69 and 23 - 1 = 22 df.

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0

2 years ago

Pls help me

masha68 [24]

Answer:

Step-by-step explanation:

Volume of the figure = Base area * height

Base area:

Base area = area of trpezium + area of triangle

Trapezium:

a, b area the length of parallel sides and h is the height of trapezium.

a = 8 m ; b = 5 m & h = 3 m

$\boxed{ \text{ Area of trapezium = $\dfrac{(a +b)*h}{2} $}}$

$=\dfrac{(8+5)*3}{2}\\\\\\=\dfrac{13*3}{2}\\\\\\= \dfrac{39}{2}\\\\\\= 19.5 \ m^{2}$

Triangle:

height = 4 m & base = 8 m

$\boxed{\text{Area of triangle =$\dfrac{1}{2}*base*height$}}$

$=\dfrac{1}{2}*8*4\\\\\\= 4*4\\\\= 16 \ m^{2}$

Base area = 19.5 + 16

= 35.5 m²

Volume of the figure = Base area * height

= 35.5 * 14

= 497 m³

8 0

3 years ago

Doses anyone know the answer?

wlad13 [49]

Answer:

Step-by-step explanation:

Symmetric since it goes up and back down the same amount of dots.

7 0

3 years ago