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vredina [299]
3 years ago
15

Solve for r. 35r-21<-35r+19

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Good morning ☕️

Answer:

r < \frac{4}{7}

Step-by-step explanation:

35r-21 < -35r+19

⇌ 35r + 35r < 19 + 21

⇌ 70r < 40

⇌ r < 40/70

⇌ r < 4/7

_________________________

:)

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Answer:

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Step-by-step explanation:

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with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1, 1)

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Question 16 (5 points)
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3 years ago
Work out the surface area of a cylinder when the height = 18cm and the volume = 1715cm cubed
lara [203]

Answer:

813.4 cm² (nearest tenth)

Step-by-step explanation:

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • h = 18cm
  • V = 1715 cm³

Use the Volume of a Cylinder formula and the given values to find the <u>radius of the cylinder</u>:

\implies \sf 1715=\pi r^2 (18)

\implies \sf r^2=\dfrac{1715}{18 \pi}

\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}

<u>Surface Area of a Cylinder</u>

\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}

Substitute the given value of h and the found value of r into the formula and solve for SA:

\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)

\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

\implies \sf SA=\dfrac{1715}{9} + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

\implies \sf SA=813.3908956...

Therefore, the surface area of the cylinder is 813.4 cm² (nearest tenth)

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