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dlinn [17]
3 years ago
5

After the diver jumps forward from the diving board the force of gravity will accelerate the diver _ to the direction of motion

Physics
1 answer:
joja [24]3 years ago
5 0
I’m unsure whether there is a question there but in forces the force weight which includes gravity would be pushing the diver directly down. However if there was enough thrust from the diver the motion would change but ultimately will be accelerating downwards because of unbalanced forces
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Which type of force is the weakest?
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Answer:

Explanation:

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The metallic bond is somewhat weaker than the ionic and covalent bond. Ionic bonds are strong electrostatic attraction forces formed between positive and negative ions. This bond is non-directional, meaning that the pull of the electrons does not favor one atom over another.

Ion-dipole forces are the strongest of the intermolecular forces. ... However, hydrogen bonds are still not as strong as ion-dipole interactions. In order from strongest to weakest, the intermolecular forces given in the answer choices are: ion-dipole, hydrogen bonding, dipole-dipole, and Van der Waals forces.

Van der Waals forces are driven by induced electrical interactions between two or more atoms or molecules that are very close to each other. Van der Waals interaction is the weakest of all intermolecular attractions between molecules

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3 years ago
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Answer:

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3 years ago
Consider a constant density gas flowing steadily over an airfoil. Far upstream the velocity is V0. Halfway along the top surface
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3 years ago
A fixed container containing an ideal gas is heated. The pressure of the gas increases because:_________
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5 0
2 years ago
Jason launches a model rocket with a mass of 2.0 kg from his spring-powered rocket launcher with a spring constant of 800 N/m. H
Arada [10]

Answer:

121 Joules

6.16717 m

Explanation:

m = Mass of the rocket = 2 kg

k = Spring constant = 800 N/m

x = Compression of spring = 0.55 m

Here, the kinetic energy of the spring and rocket will balance each other

\frac{1}{2}mu^2=\frac{1}{2}kx^2\\\Rightarrow u=\sqrt{\frac{kx^2}{m}}\\\Rightarrow u=\sqrt{\frac{800\times 0.55^2}{2}}\\\Rightarrow u=11\ m/s

The initial velocity of the rocket is 11 m/s = u.

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² = g

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11^2}{2\times -9.81}\\\Rightarrow s=6.16717\ m

The maximum height of the rocket will be 6.16717 m

Potential energy is given by

P=mgh\\\Rightarrow P=2\times 9.81\times \frac{0^2-11^2}{2\times -9.81}\\\Rightarrow P=121\ J

The potential energy of the rocket at the maximum height will be 121 Joules

5 0
4 years ago
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